## A Complete System of Mensuration of Superficies and Solids, of All Regular Figures: Calculated for the Use of Schools, Academies, and Private Learners |

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### Other editions - View all

A Complete System of Mensuration of Superfices and Solids, of All Regular ... Tobias Ostrander No preview available - 2015 |

A Complete System of Mensuration of Superfices and Solids, of All Regular ... Tobias Ostrander No preview available - 2018 |

### Common terms and phrases

12 feet 18 inches 20 inches 30 feet 9 inches abscissa acres altitude angles axis base breadth bung diameter cask cents chains chord circle circular circumference cone conjugate diameters contained convex surface cube cubic feet cubic inches cylinder diagonal difference distance divide dodecahedron equal equilateral triangle EXAMPLES feet 6 inches feet 9 feet long feet-What figure find the area find the length find the solidity foot frustrum give given globe greater greatest half head diameter height hexagon hypotenuse icosaedron inches-What less linear side measure multiply octaedron parallel perches perpendicular piece pile PROBLEM II PROBLEM VII pyramid quotient remainder Required the length Required the solidity roods Rule Rule-Divide Rule-Multiply segment solid feet specific gravity square feet square rods square root square yards stone subtract tetraedron thickness transverse diameter triangle triangular versed sine wall whole wine gallons zone

### Popular passages

Page 74 - Take the length of the keel within board (so much as she treads on the ground) and the breadth within board by the midship beam, from plank to plank, and half the breadth for the depth, then multiply the length by the breadth, and that product by the depth, and divide the whole by 94; the quotient will give the true contents of the tonnage.

Page 36 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.

Page 51 - X 40) : 60 : 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the half conjugate if the greater absciss is used.

Page 124 - Square Measure 144 square inches = 1 square foot 9 square feet = 1 square yard...

Page 121 - Add into one sum 39 times the square of the bung diameter, 25 times the square of the head diameter, and 26 times the product of the...

Page 52 - Multiply the square root of half the sum of the squares of the two axes by *, and the product will be nearly = the circumference. Ex. Taking the same example as before, we hare /24' + IT \/ = — X 3,14159 = 66,6433= the circumference nearly.