 | Francis Joseph Grund - Algebra - 1833 - 224 pages
...much does each receive ? 7) A bankrupt leaves $21,000 to be divided among four creditors, A, B, C, and D, in proportion to their claims. Now A's claim is to B's as 2 to 3 ; B's claim is to C's as 4 to 5 ; and C's claim to D's as 6 to 7. How much then does each creditor receive t С.... | |
 | William Smyth - Algebra - 1833 - 288 pages
...$830. What is the share of each ? 4 2. A bankrupt leaves $18000 to be divided among three creditors, in proportion to their claims. Now A's claim is to B's as 2 to 3, and B's claim to C's as 4 to 5. How much does each creditor receive ? 3. The sum of $539 is to be divided... | |
 | Benjamin Peirce - Algebra - 1837 - 300 pages
...may be m times, and the third n times as great as the first. a ma na 16. A bankrupt leaves $21 000 to be divided among four creditors A, B, C, D, in...proportion to their claims. Now A's claim is to B's as 2 : 3 ; B's claim : C's = 4:5; and C'a claim : D's = 6 : 7. How much does each creditor receive ? Ans.... | |
 | Benjamin Peirce - Algebra - 1837 - 302 pages
...as the first. a ma na 1 -\-m -|- n' 1 -f- "« -f- n ' 1 -f~ m -f- n' 16. A bankrupt leaves $21 000 to be divided among four creditors A, B, C, D, in proportion to their claims. Now A's claim is to J5's as 2 : 3 ; B's claim : C's = 4 : 5; and C*a claim : D's = 6:7. How much does each creditor receive... | |
 | Benjamin Peirce - Algebra - 1837 - 300 pages
...as great as the first . ama na " ns- i_|- m_|-n' i+m_|-M' i + w_|-n. 16. A bankrupt leaves $21 000 to be divided among four creditors A, B, C, D, in proportion to their claims. Now A'a claim is to B's as 2 : 3 ; B'a claim : C'a = 4:5; and C"s claim : D'a = 6:7. How much does each... | |
 | Richard W. Green - Algebra - 1839 - 156 pages
...Man 24 ; Wife 20 years. 14. A bankrupt leaves $8400 to be divided among four creditors, A, B, C, and D, in proportion to their claims. Now, A's claim is...4 to 5 ; and C's claim to D's as 6 to 7. How much must each creditor receive? Ans. A $1280 ; B $1920 ; C $2400 ; D $2800. 15. A sum of money was divided... | |
 | Benjamin Peirce - Algebra - 1843 - 308 pages
...times as great as the first. . a ma na Ans. — -—, — — , — —. 16. A bankrupt leaves $21 000 to be divided among four creditors A, B, C, D, in proportion to their claims. Now A'a claim is to B'a as 2 : 3; B's claim : C's = 4:5; and C"s claim : D'a = 6 : 7. How much does each... | |
 | Benjamin Peirce - Algebra - 1851 - 294 pages
...great as the first. Ans. a ma na at -f n' 1 -j- m -f- »' 1 -j- m + n 16. A bankrupt leaves $21 000 to be divided among four creditors A, B, C, D, in proportion to their claims. Now A's claim is to D's as 2 : 3; B's claim : C"s = 4:5; and C's claim : D's =6:7. How much does each creditor receive... | |
 | Thomas H. Palmer - Arithmetic - 1854 - 356 pages
...town raise ? Ans. A $144, B $240, and C $210. 213. The estate of a bankrupt, amounting to $21,000, is to be divided among four creditors, A, B, C, D, in proportion to their claims. Now A's claim to B's is as 2 to 3, B's claim to C's as 4 to 5, and C's claim to D's as 6 to 7. How much will each... | |
 | Thomas H. Palmer - Arithmetic - 1854 - 368 pages
...town raise ? Ans. A $144, B $240, and C $210. 213. The estate of a bankrupt, amounting to $21,000, is to be divided among four creditors, A, B, C, D, in proportion to their claims. Now A's claim to B's is as 2 to 3, B's claim to C's as 4 to 5, and C's claim to D's as 6 to 7. How much will each... | |
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Ans. 240 miles on horseback, 840 miles by water, and 1960 miles on foot. 15. Divide the number a into three such parts, that the second may be m times, and the third n times as great as the first. 
