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" GB is equal to E, and CK to F ; therefore AB is the same multiple of E, that KH is of F: But AB... "
The Elements of Euclid: With Dissertations Intended to Assist and Encourage ... - Page 8
by Euclid, James Williamson - 1781 - 309 pages
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - Trigonometry - 1762 - 488 pages
...multiple of F, that CD is of F ; wherefore : KH i& equal to CD". take away the common magnitude CH, then the remainder KC is equal to the remainder HD. but KC is equal to F, HD therefore is equal to F. But let GB be a multiple of E ; then HD is the fame multiple of F. Make...
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ...

Robert Simson - Trigonometry - 1775 - 534 pages
...of F, that CD is of F ; wherefore KH is equal to CD • : Take a' way the common magnitude CH, then the remainder KC is equal to the remainder HD : But KC is equal to F ; HD therefore is equal to F. But let GB be a multiple of E ; then „ HD is the farne multiple of...
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The First Six Books: Together with the Eleventh and Twelfth

Euclid - 1781 - 552 pages
...CD is of F; • i. At. 5. wherefore KH is equal to CD • : Take away the common magnitude CH, then the remainder KC is equal to the remainder HD : But KC is equal to F ; HD therefore is equal to F. But let GB be a multiple of E ; then HD is the fame multiple ot F : Make...
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The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ...

Robert Simson - Trigonometry - 1804 - 530 pages
...that CD is of F ; wherefore 1. *. Ax. 5. KH is equal to CD a. take away the common magnitude CH, then the remainder KC is equal to the remainder HD. but KC is equal to F, HD therefore is equal to F. ' But let GB be a multiple E; then HD is the fame multiple of F, Make CK...
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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclides - 1816 - 588 pages
...• 1 Ax. s. is of F; wherefore KH is equal to CD a: 15 3) KF Take away the common magnitude CH, then the remainder KC is equal to the remainder HD: But KC is equal to F ; HD therefore is equal to F. But let GB be a multiple of E; then v HD is the same multiple of F: Make...
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The First Six Books of the Elements of Euclid, with a Commentary and ...

Euclid, Dionysius Lardner - Euclid's Elements - 1828 - 542 pages
...CD is of F : wherefore KH is equal (Ax. I.) to CD : take away BD k K the common magnitude CH, then the remainder KC is equal to the remainder HD : but KC is equal (const.) to F : therefore HD is equal to F. Next let GB be a multiple of E ; HD shall be the same multiple...
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The Elements of Euclid; viz. the first six books, together with the eleventh ...

Euclides - 1834 - 518 pages
...multiple of F, that CD is of F i wherefore KH is equal * to CD : take away the common magnitude CH, then the remainder KC is equal to the remainder HD : but KC is equal t | Constr. to F ; therefore HD is equal to F. Next, let GB be a multiple of E : HD shall be the same...
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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclid - 1835 - 540 pages
...Talrn •" ^ K a 1. Ax. 5. wherefore, KH is equal to CD a : Take away the common magnitude CH, then the remainder KC is equal to the remainder HD: but KC is equal to F, HD therefore is equal to F. Next, Let GB be a multiple of E ; then will HD be the same multiple of...
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The First Six and the Eleventh and Twelfth Books of Euclid's Elements: With ...

Euclid, James Thomson - Geometry - 1837 - 410 pages
...same multiple of F, that CD is of F; wherefore (V. ax. 1.) KH is equal to CD. Take away ('1 1, then the remainder KC is equal to the remainder HD : but KC is equal to F; HD thereforeis equal to F. But let GB be a multiple of E ; then HD is the same multiple of F. Make...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - Geometry - 1838 - 434 pages
...that CD is of F ; wherefore KH is equal to CD (1. Ax. 5.) : take away the common magnitude CH, then the remainder KC is equal to the remainder HD ; but KC is equal to F; HD therefore is equal to F. But let GB be a multiple of E : then HD is the same multiple of F : make...
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