| John Bonnycastle - Trigonometry - 1806 - 464 pages
...be 2 miles, and the radius of the earth DC 3979 miles. Ans. dist. AC 126 miles. 9. From a window A, near the bottom of a house, which seemed to be on a level with the bottom of a church GD, I took the Z of elevation GAD of the top of the steeple equal to 4O° ; and from another... | |
| Charles Hutton - Mathematics - 1807 - 464 pages
...top of the tower to be 33° 45'. What then is the height of the tower? Ans. 93-33148 feet. EXAM. xv. From a window near the bottom of a house, which seemed...took the angle of elevation of the top of the steeple equal 40°; then from another window, 18 feet directly above the former, the like angle was 31° 30'... | |
| Samuel Webber - Mathematics - 1808 - 520 pages
...9'8255109 2'12O5739 2'2890380 109° 8 ZB A AD AB 28'63 9'9756701 9' 1435553 2'289038O 1 '4569232 104 2. From a window near the bottom of a house, which seemed to be upon a level with the bottom of a steeple, I took the angle of elevation of the top of the steeple... | |
| Charles Hutton - Mathematics - 1811 - 494 pages
...top of the tower to be 33° 45'. What then is the height of the tower ? Ans. 93-33148 feet. EXAM. xv. From a window near the bottom of a house, which seemed to be on a level with the bottom of a steeple, 4 took the angle of elevation of the top of the steeple equal 40°; then from another window, 18 feet... | |
| Charles Hutton - Mathematics - 1811 - 442 pages
...top of the tower to be 33° 45'. What then is the height of the tower? Ans. 93-33148 feet. EXAM. xv. From a window near the bottom of a house, which seemed to b« on a level with the bottom of a steeple, 1 took the angle of elevation of the top of the steeple... | |
| Charles Hutton - Arithmetic - 1818 - 646 pages
...height of the tower ? Ans. 93-33148 feet EXAM. xv. From a window near the bottom of a house, whir:h seemed to be on a level with the bottom of a steeple, 1 took the angle of elevation ot the top of the steeple equal 40° : then from another window, 18 feet... | |
| Charles Hutton - Mathematics - 1822 - 616 pages
...of the towers to be 23° 46'. What then is the height of the tower ? Ans. 93.33148 feet. EXAM. xv. From a window near the bottom of a house, •which...took the angle of elevation of the top of the steeple equal 40° ; then from another window, 18 feet directly above the former, the like angle was 37° 30'... | |
| Charles Hutton - Mathematics - 1831 - 632 pages
...the top of the tower to be 33° 45'. What is the height of the tower ? Ans. 93-33148 feet. EXAM. xv. From a window near the bottom of a house, which seemed to be on a level with the bottom of a steeple, I look the angle of elevation of the top of the steeple equal 40° ; then from another window, 18 feet... | |
| Charles Hutton - Mathematics - 1831 - 660 pages
...angle to the top of the tower to be 33° 45'. What is the height of the tower? Ans. 93-33148 fèet. ф I took the angle of elevation of the top of the steeple equal 40° ; then from another window, 18 feet direct)}' above the former, the like angle was 37" :... | |
| Robert Gibson - Surveying - 1832 - 290 pages
...measured 35°. What then was the ship's distance from the bottom of the wall ? Ans. 204.22 feet. Ex. 3. From a window near the bottom of a house which seemed to be on a level with the bottom ofa steeple, I took the angle of elevation of the top of the steeple, equal -10° ; then from another... | |
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