First Year Algebra
D.C. Heath & Company, 1912 - Algebra - 327 pages
What people are saying - Write a review
We haven't found any reviews in the usual places.
Other editions - View all
Common terms and phrases
added algebra altitude amount angle arithmetic base called changed CHECK coefficient common complete containing denominator difference digits distance divided division divisor Draw equal equation EXAMPLE exceeds EXERCISE exponent Express factors feet figure Find Find the number formula fraction given gives going graph greater hand hour inches increased indicated integral interest invested length less lowest means method miles minute monomial Multiply negative NOTE obtained parentheses perfect placed polynomial positive pounds problems proportion quadratic quotient rectangle Reduce remainder represent result Rule side Simplify smaller SOLUTION Solve Solve the equation spaces square root step Substitute subtract temperature third train triangle twice units unknown variables varies weight Write
Page 293 - In any proportion, the product of the means is equal to the product of the extremes.
Page 256 - In a right triangle the square of the hypotenuse equals the sum of the squares of the other two sides or legs.
Page 167 - Therefore, when the numerator and denominator of a fraction are both multiplied by the same number, the...
Page 92 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 97 - Both members of an equation may be multiplied by the same number without destroying the equality.
Page 291 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D ; and read, A is to B as C to D.
Page 200 - A Literal Equation is one in which some or all of the known quantities are represented by letters.
Page 236 - A and B working together can do a piece of work in 12 days.
Page 246 - ... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor...
Page 88 - That is, the exponent of a letter in the quotient is equal to its exponent in the dividend minus its exponent in the divisor. For example, — = a*~".