 | Oliver Welch - Arithmetic - 1812 - 236 pages
...area of a circle whose circumference is 44 rods ? 44X 44 X -07958= 1 54-06688, Ans. >» PROBLEM VI. The area of a circle given to find the diameter. RULE. Divide the area by 0-7854 and extract the square root of the guotent ; the root is the diameter sought. (See application... | |
 | Beriah Stevens - Arithmetic - 1822 - 436 pages
...the area of a circle whose circumference is 44 1 44 X44 X ,07958, = 1 54,06608, answer. PROBLEM 16lh. The area of a circle given, to find the diameter. RULE. Divide the area by ,7854 and extract the equare root of the quotient ; the root ivill be the diameter sought.... | |
 | William Kinne - 1829 - 246 pages
...the area of a circle whose circumference is 30 rods? 30 x30x, 07958=7 1,62200 rods. Ans. PROBLEM 1V. The area of a circle given to find the diameter. RULE. — Divide the area by ,7854 — and the square root ef the quotient is the required diameter. EXAMPLES. 1. Required... | |
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...diar meter is 6 rods, at the rate of 8 cents per square foot ? Ans. 615,816432 dollars. PROBLEM IV. The area of a circle given, to find the diameter. Rule — Divide the area by the decimal ,7854, and extract the square root of the quotient. EXAMPLES. 1. The area of a... | |
 | Arithmetic - 1841 - 200 pages
...What is the area of a circle whose circumference IB 44 rods? 44X44X-07953=154-0668S., Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — (!). Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. (See application... | |
| |
Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE.—(') Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. 