A Key to the Western Calculator: Containing the Solution of All the Examples and Questions for Exercise, Whith Reference to the Pages where They Stand, to which is Added, Some Useful Rules, Designed Chiefly to Facilitate the Labour of Teachers ; and Assist Such as Have Not the Opportunity of a Tutor's Aid

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Johnston & Stockton, 1831 - Arithmetic - 139 pages
 

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Page 2 - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Page 47 - State the question, by placing the three conditional terms in this order : that which is the principal cause of gain, loss, or action, possesses the first place ; that which denotes space of time or distance of place, the second ; and that which -is the gain, loss, or action, the third ; then place the other two terms, which move the...
Page 2 - Congress of the United States, entitled "an act for the encouragement of learning, by securing the copies of maps, charts, and books, to the authors and proprietors of such copies, during the time therein mentioned." And also to an act entitled "an act supplementary to an act entitled an act for the encouragement of learning, by securing the copies of maps, charts, and books, to the authors and proprietors of such copies, during the times therein mentioned, and extending the benefits thereof to the...
Page 139 - Multiply the half sum and the three remainders continually together, and the square root of the product will be the area...
Page 47 - ... first for a divisor; but if the blank fall under the first or second place, multiply the first, second and last terms together for a dividend, and the other two for a divisor ; and the quotient will be the answer.
Page 2 - In conformity to the Act of the Congress of the United States, entitled " An Act for the encouragement of Learning, by securing the copies of Maps, Charts, and Books to the author* and proprietors of such copies, during the time therein mentioned.
Page 97 - Defective divisors, after the first, may be more concisely found thus: To the last complete divisor, add the number which completed it with twice the square of the last figure in the root, and the sum will be the next defective divisor.
Page 139 - RULE II. Any two sides of a triangle being multiplied together, and the product again by half the natural sine of their included angle, will give the area of the triangle.
Page 94 - Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE.—(') Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought.

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