| Euclid, James Thomson - Geometry - 1837 - 410 pages
...made a tangent to a circle, and if through the extremity of the tangent a line be drawn cutting the circle, so that the part within the circle may be equal to AD, DE will be equal to the external part : whence the construction is manifest. is the complement... | |
| William Frothingham Bradbury - Geometry - 1872 - 124 pages
...triangle similar to a given triangle. 92, Through a given point to draw to a given circle a secant such that the part within the circle may be equal to a given line. 93, With a given radius to draw a circumference, 1st. Through two given points. 2d. Through a... | |
| William Frothingham Bradbury - Geometry - 1872 - 262 pages
...triangle similar to a given triangle. 92. Through a given point to draw to a given circle a secant such that the part within the circle may be equal to a given line. 93. With a given radius to draw a circumference, 1st. Through two given points. 2d. Through a... | |
| Euclid, James Bryce, David Munn (F.R.S.E.) - Geometry - 1874 - 236 pages
...three given circles; consider the four cases. 58. Through a given point draw a straight line cutting a circle, so that the part within the circle may be equal to a given line. When is the problem impossible ? 59. Through a given point without a circle, to draw a line cutting... | |
| William Frothingham Bradbury - Geometry - 1880 - 260 pages
...triangle similar to a given triangle. 92. Through a given point to draw to a given circle a secant such that the part within the circle may be equal to a given line. 93i With a given radius to draw a circumference, 1st. Through two given points. 2d. Through a... | |
| Henry Martyn Taylor - Euclid's Elements - 1895 - 708 pages
...CA, A0. 128. Through a given point without a circle draw, when possible, a straight line cutting the circle so that the part within the circle may be equal to the part without the circle. What condition is necessary in order that a real solution may be possible?... | |
| 268 pages
...AB. 283, 128. Through a given point without a circle draw, when possible, a straight line cutting the circle so that the part within the circle may be equal to the part without the circle. What condition is necessary in order that a real solution may be possible?... | |
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