The tutor's assistant

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Page 92 - To reduce a mixed number to an improper fraction. RULE. Multiply the whole number by the denominator of the fraction, and to the product add the numerator for a new numerator, and place it over the denominator. 1. Reduce 127T^ to an improper fraction.
Page 145 - Multiplier. 2. Multiply each term in the Multiplicand (beginning at the lowest) by the feet in the Multiplier...
Page 112 - To extract the Square Root of a Vulgar Fraction. RULE, Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator. NOTE.-— If the fraction be...
Page 93 - Го reduce a fraction of one denomination to the fraction of another, but greater, retaining the same value. RULE. Reduce the given fraction to a compound one by comparing it with all the denominations between it and that denomination you would reduce it to ; then reduce that compound fraction to a simple one, by Case V.
Page 98 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 82 - I. When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question, are equal to a given quantity of the last.
Page 114 - The top of a castle from the ground is 45 yards high, and is surrounded with a ditch 60 yards broad ; what length must a ladder be to reach from the outside of the ditch to the top of the castle ? Ans.
Page 74 - Ib. at 4s. per Ib., how much of each sort must he take to make the composition worth 8s. per Ib.
Page 93 - RULE. — Multiply all the numerators together for a new numerator, and all the denominators for a new denominator ; then reduce the new fraction to its lowest terms.
Page 89 - To his executors 50, his youngest son was to have as much more as the executors, and each son to exceed the next younger by as much more ; what was the eldest son's portion? Ans. 25600. The first term, ratio, and number of terms given, to find the sum of all the terms.

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