| Albert Edward Seaton - 1886 - 520 pages
...path so found is like an attenuated figure 8 in head-gear, and somewhat more pronounced in sterngear. **The arc of a circle of radius equal to the length of** the suspension or bridle rods, is then drawn through each of these figures in such a way that there... | |
| Albert Edward Seaton - Marine engineering - 1886 - 518 pages
...path so found is like an attenuated figure 8 in head-gear, and somewhat more pronounced in sterngear. **The arc of a circle of radius equal to the length of** the suspension or bridle rods, is then drawn through each of these figures in such a way that there... | |
| Emory Edwards - Marine engineering - 1891 - 416 pages
...path so found is like an attenuated figure 8 in head-gear, and somewhat more pronounced in stern-gear. **The arc of a circle of radius equal to the length of** the suspension or bridle rods, is then drawn through each of these figures in such a way that there... | |
| 1902 - 484 pages
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| American School (Chicago, Ill.) - Engineering - 1903
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| American School (Lansing, Ill.) - Architectural drawing - 1906 - 432 pages
...at the same distance from the vertfix. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| American School (Chicago, Ill.) - Engineering - 1906 - 582 pages
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| Drawing - 1906 - 424 pages
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| American School (Lansing, Ill.) - Architecture - 1907 - 360 pages
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
| Frederick Eugene Turneaure - Civil engineering - 1908 - 474 pages
...at the same distance from the vertex. From this it follows that the development of the base will be **the arc of a circle of radius equal to the length of an element.** To find the length of this arc which is equal to the distance around the base, divide the plan of the... | |
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