 | William Templeton (engineer.) - 1846 - 236 pages
...whole circumference of the sphere, and the product is the curved surface. RULE 2. — Add the square of the height to three times the square of the radius...base ; multiply that sum by the height, and by .5236, and the product is the solid content. EXAMPLE 1. — The diameter AB of the sphere ABCD = 20 inches... | |
 | William Templeton (engineer.) - 1852 - 284 pages
...the curved surface. RULE 2. — Add the square of the height to three times the square of the .adius of the base; multiply that sum by the height, and by '5236, and the product is the solid content. EXAMPLE 1. — The diameter AB of the sphere ABCD = 20 inches... | |
 | Charles Haslett - Engineering - 1855 - 482 pages
...the whole circumference of the sphere, .and the product is the curved surface. RULE 2. Add the square of the height to three times the square of the radius of the base ; multiply that sum b3' the height, and by -5236, and the. product is the solid content. EXAMPLE 1. The diameter AB of... | |
 | Charles Haslett - 1855 - 544 pages
...the whole circumference of the sphere, and the product is the curved surface. RULE 2. Add the square of the height to three times the square of the radius...base ; multiply that sum by the height, and by -5236, and the product is the solid content. EXAMPLE 1. The diameter AB of the sphere ABCD = 20 inches ; what... | |
 | Charles W. Hackley - Engineering - 1856 - 530 pages
...the whole circumference of the sphere, and the product is the curved surface. RULE 2. Add the square of the height to three times the square of the radius...; multiply that sum by .the height, and by *5236, and the product is the solid content. EXAMPLE 1. The diameter AB of the sphere ABCD = 20 inches; what... | |
 | Charles Haslett, Charles William Hackley - Engineering - 1859 - 574 pages
...the whole circumference of the sphere, an j the product is the curved surface. RULE 2. Add the square of the height to three times the square of the radius of tlie base ; multiply that sum by the height, and by -5236, and the product is the solid content. EXAMPLE... | |
 | Henry S. Merrett - 1863 - 428 pages
...circumference of the sphere, the product is the curve surface. To find the solidity, add the square of the height to three times the square of the radius...multiply that sum by the height and by .5236, the product will be the solid content. The diameter AВ of the sphere AВСD = 35.813 inches; what is the convex... | |
 | Henry S. Merrett - 1863 - 476 pages
...circumference of the sphere, the product is the curve surface. To find the solidity, add the square of the height to three times the square of the radius...multiply that sum by the height and by .5236, the product will be the solid content. The diameter AB of the sphere ABCD = 35.813 inches; what is the convex surface... | |
 | Popular educator - 1884 - 910 pages
...supposing it a regular sphere ? To find tho solid content of a segment of a sphere, add the square of its height to three times the square of the radius of the base. Multiply the sum by the height, and that product by "g EXAMPLE. What is the content of the segment of a sphere... | |
 | John Kelley Ellwood - Algebra - 1892 - 312 pages
...Multiply the cube of the diameter by .5230. 34. Volume of a Segment of a Sphere. — Add the square of the height to three times the square of the radius of the base, and multiply the sum by the product of the height by .5230 ; or subtract twice the height of the segment... | |
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Add the square of the height to three times the square of the radius of the base ; multiply that sum by .the height, and by *5236, and the product is the solid content. 
