 | Nicolas Pike - Algebra - 1808 - 470 pages
...series together, belonging to those indices, and make the product a dividend. 4>. Raise the first term to a power, whose index is one less than the number of terms multiplied, and make the result a divisor, by which divide the dividend, and the quotient will... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...series together belonging to those indices, and make the product a dividend. 4. Raise tha first term to a power whose index is one less than the number of the terms multiplied, and make the result a divisor. 5. Divide, and the quotient is the term sought. EXAMPLE8.... | |
 | Arithmetic - 1818 - 264 pages
...together, belonging to those indices, and make the product a dividend. • 4. Raise the first term to a power whose index is one less than the number of terms multiplied, and make the result a diivisor. 5. Divide the dividend by the divisor, and the quotient... | |
 | Jeremiah Day - Algebra - 1820 - 352 pages
...continued proportion, the ratio of the first to the last is equal to one of the intervening ratios raised to a, power whose index is one less than the number of quantities. If there are /ciMrgfoportionalsff, b, c, d, then a:d::a3 :63. If there are five a,b,c,d,e,... | |
 | Nathan Daboll - Arithmetic - 1820 - 256 pages
...series together belonging to those indices, and make the product a dividend. 4. Raise th» first term in a power whose, index is one less than the number of the terms multiplied, and make the result a divisor. 5. Divide, and the quotient is the term sought. EXAMPLES.... | |
 | Nicolas Pike - Arithmetic - 1822 - 536 pages
...2X2', 2Xi3, '-!X23, 2X24, and so on. Any term after the firat is evidently that power of the rutio whose index is one less than the number of the term multiplied by the first term. Thus, the 3d term is 2X2" ; the 4th term is 2X23, and tlie 8th term •would be 2X2T, ami so on. In... | |
 | Nicolas Pike - Arithmetic - 1822 - 562 pages
...2X2>, 8X?a, 2X21. 2X2-', anil so on. Any term alter the first is evidently that power of the ratio whose index is one less than the number of the term multiplied by the lint term. Thus, the 3d term is 2x2^ ; the 4th term is2X2:1, aud the ittli term would be 2X27. and... | |
 | Nicolas Pike - Arithmetic - 1832 - 538 pages
...2X2',2XS',andsoon. Any term after tlie first is evidently that rnwerof the ratio whose index is с ne less than the number of the term multiplied by the first term. Thus, tlie 3d term is 2X2' ; the 4th 'term is 2X23, »nil Ihn üth term would be 2x27i und soon. In... | |
 | Enoch Lewis - Arithmetic - 1824 - 92 pages
...first term being multiplied once by the ratio for every subsequent term, the ratio will evidently rise to a power whose index is one less than the number of terms. (50.) To find the sum of the series. First, suppose the ratio 2; and let AB, EC, CD, denote... | |
 | Jeremiah Day - Algebra - 1827 - 352 pages
...continued proportion, the rjitio of the first to the last is equal to one of the intervening ratios raised to a power whose index is one less than the number of quantities. If there are four proportionals a, b, c, d, then a : d; '.a3 : b3. If there are five •... | |
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Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise... 
