The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for the Use of Schools in the United States |
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Page 40
... cubic measure . A solid inch is a body , or block , having six sides , each of which is an inch square , and the number of inches in a solid foot is equal to the number of such blocks that would be required to make a pile a foot square ...
... cubic measure . A solid inch is a body , or block , having six sides , each of which is an inch square , and the number of inches in a solid foot is equal to the number of such blocks that would be required to make a pile a foot square ...
Page 41
... CUBIC MEASURE . 1728 inches , in . make 1 foot , ft . in . 1728 feet 1 yard | cord 27 feet " 1 yard , yd . 46656 27 1 128 feet " 1 cord , cor . 221184 128 429 1 40 ft . of round timber , or 50 ft . of hewn timber , make 1 ton , ton . XI ...
... CUBIC MEASURE . 1728 inches , in . make 1 foot , ft . in . 1728 feet 1 yard | cord 27 feet " 1 yard , yd . 46656 27 1 128 feet " 1 cord , cor . 221184 128 429 1 40 ft . of round timber , or 50 ft . of hewn timber , make 1 ton , ton . XI ...
Page 42
... cubic 70 qt . 1 gal . bar..hhd . gal . inches 282 bar . 41 10152 144 S 11 1 hogshead , hhd . || 15228 216 54 1 호 1 4 quarts " 1 gallon , 36 gallons " 1 barrel , 54 gallons 66 XIII . DRY MEASURE . 2 pints , pts . make 1 quart , qt . 4 ...
... cubic 70 qt . 1 gal . bar..hhd . gal . inches 282 bar . 41 10152 144 S 11 1 hogshead , hhd . || 15228 216 54 1 호 1 4 quarts " 1 gallon , 36 gallons " 1 barrel , 54 gallons 66 XIII . DRY MEASURE . 2 pints , pts . make 1 quart , qt . 4 ...
Page 54
... cubic inches , | should pay D. 2. How many seconds from the birth of Christ to the end of the year 1824 , allowing 365d . 5h . 48m . 57s . to a year ? Ans . 57559853088 . 3. How many seconds in 8s . 12 ° 14 ′ 26 " ? Ans , 908066 . 4. How ...
... cubic inches , | should pay D. 2. How many seconds from the birth of Christ to the end of the year 1824 , allowing 365d . 5h . 48m . 57s . to a year ? Ans . 57559853088 . 3. How many seconds in 8s . 12 ° 14 ′ 26 " ? Ans , 908066 . 4. How ...
Page 56
... cubic inches , | should pay D $ 100 ; and Q how many cords of wood ? said C. should pay D $ 55 ; but R said D should pay C $ 25 ; how was the matter settled ? REVIEW . SECTION V. PER CENT . 161. Per Cent . is. Ans . 25 cords . 35. A and ...
... cubic inches , | should pay D $ 100 ; and Q how many cords of wood ? said C. should pay D $ 55 ; but R said D should pay C $ 25 ; how was the matter settled ? REVIEW . SECTION V. PER CENT . 161. Per Cent . is. Ans . 25 cords . 35. A and ...
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Common terms and phrases
3qrs acres Addition amount ANALYSIS answer bush bushels called ciphers circumference column common denominator common difference compound interest contains cost cube root cubic decimal decimal places denoted diameter divi divide dividend division dollars dolls DRY MEASURE equal evidently expressed factors Federal Money feet long foot gain gallon given number given to find greatest common divisor Hence hundred hundredths inches last term least common multiple left hand leger lemons length man's share measure merator method miles minuend mixed number multiplicand multiply number of figures number of terms payment pence pound present worth principal proportion quantity quarts QUESTIONS FOR PRACTICE ratio Reduce remainder right hand rods RULE RULE.-Multiply shillings side simple square root subtract subtrahend supposed tens tenths tion Troy weight units velocity vulgar fraction weight whole number write
Popular passages
Page 82 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments ; the quotient will be the average term of credit.
Page 89 - The greatest common divisor of two or more numbers, is the greatest number which will divide them without a remainder. Thus 6 is the greatest common divisor of 12, 18, 24, and 30.
Page 118 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 111 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend...
Page 94 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 120 - Add together the most convenient indices to make an index less by 1 than the number expressing the place of the term sought. 3. Multiply the terms of the geometrical series together belonging to those indices, and make the product a dividend. 4. Raise...
Page 115 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 31 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Page 2 - Los números cardinales 0: zero 1: one 2: two 3: three 4: four 5: five 6: six 7: seven 8: eight 9: nine 10: ten 11: eleven 12: twelve 13: thirteen 14: fourteen 15: fifteen 16: sixteen 17: seventeen 18: eighteen 19: nineteen 20: twenty...
Page 93 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.