 | Charles Vyse - Arithmetic - 1785 - 350 pages
...1 . Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or,... | |
 | Charles Hutton - Measurement - 1788 - 728 pages
...the area CAE of the whole circle or feftor accordingly. ^_. £. D. * RULE II. « Multiply the fquare of the diameter by '7854, and the product will be the area* EXAMPLES. i, What is the area of a circle whofe diameter is I, and circumference 3'i4i6? Vl4-l6 XI... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...RULES. 1. Multiply Half the Circumference by Half the Diameter, and tin- Product will 1& the Area. Or, 2. Multiply the Square of the Diameter by ,7854, and the Product will be the Area. Or, 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or, 4.... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...circumference^ and the product is the area ; or if the diameter is given without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLE8. 1. Required the area of a circle whose diameter 'is 12 inches, and circumference 37,7 inches.... | |
 | Thomas Keith - 1817 - 306 pages
...' the area of a circle whose diameter is d. circumference and diameter, 'and it will give the area. 2. Multiply the square of the diameter by 7854, and the product will be the area. 3. As 452 is to 355, so is the square of the diamuter to the area. 3' "3 : 355 :: diameter I : circumference... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...circumference, and the product is the area ; or if the diameter is given • •without the circumference, multiply the square of the diameter by ,7854 and the product will be- the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches.... | |
 | William Jillard Hort - 1822 - 308 pages
...circle. Rule 1. Multiply half the circumference by half the diameter, and the product will be the area. Rule 2. Multiply the square of the diameter by 7854', and the product will be the area. ProUem. To find the area of an ellipse. Multiply the product of the two axes, by the number 7854. for... | |
 | Nicolas Pike - Arithmetic - 1822 - 562 pages
...1 5. The Diameter being given to find the Area of a Circle without finding the Circumference. RULE. Multiply the square of the diameter by -7854,* and the product will be the area of the circle, whose diameter was given. EXAMP. The diameter of a circle being 12, to find the area... | |
 | James Mitchell - Mathematics - 1823 - 666 pages
...Diameter being given. 1. Multiply the diameter by 3-14159, and the product will be the circumference. 2. Multiply the square of the diameter by -7854, and the product •will be the area. Or general, if we put diameter = D, circumference = C, area — A, and 3-141S9 = 1', we have the following... | |
 | Nathan Daboll - Arithmetic - 1825 - 248 pages
...circumference' and the product is the area; or if the diameter is ^iven vdthout the circumference, multiply the square of the diameter by ,7854 and the product will be the urea. EXAMPLES. 1. Required Hie area of a circle whose diameter is 12 inches, and circumference 37,7... | |
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... multiply the square of the diameter by ,7854 and the product will be- the area. 
