A Treatise on Trigonometry, Plane and Spherical: With Its Application to Navigation and Surveying, Nautical and Practical Astronomy and Geodesy : with Logarithmic, Trigonometrical, and Nautical Tables, for the Use of Schools and Colleges |
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Page 27
... hypothenuse of the triangle does to the side opposite the acute angle . It is customary , for conciseness , to represent the sides opposite the angles of a triangle by small letters of the same name with the large let- ters which are ...
... hypothenuse of the triangle does to the side opposite the acute angle . It is customary , for conciseness , to represent the sides opposite the angles of a triangle by small letters of the same name with the large let- ters which are ...
Page 29
... hypothenuse is required . Formula ( 1 ) of the last article applied to this case gives * 1 sin 350 :: a : 15 Multiplying the extremes and dividing by the first mean the value of the other mean which is a , the hypothenuse required ...
... hypothenuse is required . Formula ( 1 ) of the last article applied to this case gives * 1 sin 350 :: a : 15 Multiplying the extremes and dividing by the first mean the value of the other mean which is a , the hypothenuse required ...
Page 30
... hypothenuse is equivalent to the sum of the squares upon the other two sides . height of the roof be 12 feet , and the semi - breadth 16 feet , then Let the whence , a2 = 122 + 16 ' = 400 a = 20 If the length of the rafters had been ...
... hypothenuse is equivalent to the sum of the squares upon the other two sides . height of the roof be 12 feet , and the semi - breadth 16 feet , then Let the whence , a2 = 122 + 16 ' = 400 a = 20 If the length of the rafters had been ...
Page 31
... hypothenuse not entering into the prob- lem , neither of the above formulas , all of which contain the hypothenuse , would serve to find the side required in a direct manner . It might , how- ever , be found indirectly by first finding ...
... hypothenuse not entering into the prob- lem , neither of the above formulas , all of which contain the hypothenuse , would serve to find the side required in a direct manner . It might , how- ever , be found indirectly by first finding ...
Page 54
... hypothenuse Ī± = 10 X 15 sin 35 Ā° employing 100 as R , instead of 1 , because the tables which we are about to use are constructed with that value of R , we have , by the rules for multiplication and division of logarithms log . of 101o ...
... hypothenuse Ī± = 10 X 15 sin 35 Ā° employing 100 as R , instead of 1 , because the tables which we are about to use are constructed with that value of R , we have , by the rules for multiplication and division of logarithms log . of 101o ...
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Common terms and phrases
A.M. Hour P.M. altitude azimuth centre circle colatitude collimation column comp cosĀ² cosc Cosecant Cotangent Diff Cotangent Secant course decimal declination departure determined diagram difference of latitude difference of longitude distance divided equal equation error EXAMPLE expressed feet formula Geom given number hence horizontal Hour A.M. Cosine Hour A.M. Hour hour angle hypothenuse instrument Logarithms of Numbers longitude meridian miles multiplied Napier's rules Natural Sines Nautical Almanac negative number of degrees observed obtained parallel parallel sailing perpendicular plane sailing plane triangle Prop proportion quadrant quotient radius right angled triangle right ascension sailed screw second member ship side opposite siderial sin a cos sin a sin sinĀ² sine and cosine solution sphere spherical triangle spherical trigonometry spirit level star subtracting supporting axis TABLE XXVII tangent telescope transit trigonometrical lines vertical zenith