... a scale of 100 rods to an inch, in which case the side AB will be represented by 4.32 inches ; or we may construct it upon a scale of 200 rods to an inch ; that is, 100 rods to a half inch, which is very conveniently done from a scale on which a half... Elements of Plane and Spherical Trigonometry - Page 45by Elias Loomis - 1865 - 150 pagesFull view - About this book
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...Having given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the re maining parts. For this case we employ equation (1.) ; As sin a : sin b : : sin A : sin B. Ex. 1.... | |
| James Elliot - 1851 - 162 pages
...Ans. 63° 55' + , or 116° 5'- ; and 67° 38'-, or 15° 28' ±. PROBLEM IV. In any Triangle, having given two Sides and an Angle opposite one of them, to find the third Side. RULE. Find the angles by Problem in, and then the third side by Problem n. NOTE. When the... | |
| Adrien Marie Legendre - Geometry - 1852 - 436 pages
...Having given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the remaining parts. 19. For this case, we employ equations (3) ; sin a : sin & : : sin A Ex. 1. Given... | |
| Charles Davies - Geometry - 1854 - 436 pages
...Having given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the remaining parts. 19. For this case, we employ proportions (3); sin a : sin b : : sin A .Ex. 1. Given... | |
| Elias Loomis - Logarithms - 1859 - 372 pages
...two angles and the included side. 5. Given the three sides. 6. Given the three angles. CASE I. (219.) Given two sides and an angle opposite one of them, to find the remaining parts. In the triangle ABC, let there be given the two sides AC and BC, and the angle A opposite... | |
| Adrien Marie Legendre - Geometry - 1863 - 464 pages
...25", and a = 305.296 ft., to find A, b, and c. . A = 91° 23', 5 = 238.1978 ft., c = 185.3 ft. CASE II. Given two sides and an angle opposite one of them, to find the remaining parts. 44. The solution, in this case, is commenced by finding a second angle by means of... | |
| Elias Loomis - Geometry - 1871 - 302 pages
...A, 45° 30', the angle B, 35° 20', and the side AB, 43° rods, to construct the triangle, and find the lengths of the sides AC and BC. The triangle ABC...Ex. 2. Given the angle A, 48°, the angle C, 113°, ajid the side AC, 795, to construct the triangle. II. Given two sides and an angle opposite one of... | |
| Charles Davies - Geometry - 1872 - 464 pages
...25", and a = 305.296 ft., to find A, b, and c. Ana. A = 91° 23', * = 238.1978 ft., c = 185.3 ft. CASE II. Given two sides and an angle opposite one of them, to find the remaining parts. 44. The solution, in this case, is commenced by finding a second angle by means of... | |
| Charles Davies - 1874 - 464 pages
...25", and a = 305.296 ft., to iind A, b, and c. Ana. A - 91° 23', b = 238.1978 ft., c = 185.3 ft. CASE II. Given two sides and an angle opposite one of them, to find t/te remaining parts. 44. The solution, in this caso, is commenced by finding & second angle by means... | |
| Adrien Marie Legendre - Geometry - 1874 - 500 pages
...25", and a = 305.296 ft., to find A, b, and c. Ans. A = 91° 23', 6 = 238.1978 ft., C = 185.3 ft. CASE II. Given two sides and an angle opposite one of them, to find tlie remaining parts. 44. The solution, in this case, is commenced by finding & second angle by means... | |
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