 An angle inscribed in a circle is measured by one-half the intercepted arc. In this case, the angle intercepts one-fourth the circumference, and is measured by one-eighth the circumference, or by 360° X 5- = 45°.  Answers to questions - Page 95by International Correspondence Schools - 1901Full view - About this book
 | 1897 - 358 pages
....938 sq. in. Hence, the area of the whole figure = .656 + .188 -f- .938 = 1.78 + sq. in. Ans. (23O) An angle inscribed in a circle is measured by onehalf...measured by one-eighth the circumference, or by 360° 45° in the angle. Ans. V 1 X g — Hence, there are (231) Since this is a regular hexagon, it may... | |
 | International Correspondence Schools - 1900 - 282 pages
...X.75 = 1.25X .75= .938 sq. in. Hence, the area of the whole figure = . 656 + . 188 -f- . 938 = 1.78 + sq. in. Ans. (181) An angle inscribed in a circle...the circumference, or by 360° X 5- = 45°. Hence, о there are 45° in the angle. Ans. (182) Since this is a regular hexagon, it may be inscribed in... | |
 | Nels Johann Lennes, Archibald Shepard Merrill - Logarithms - 1928 - 300 pages
...altitude. (12) A tangent to a circle is perpendicular to the radius drawn to the point of tangency. (13) An angle inscribed in a circle is measured by one-half the intercepted arc. In solving regular polygons (see page 52) use is made of the theorem : (14) A circle may be circumscribed... | |
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