... 07958 in using the circumferences j then taking one-third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each side of the greater end being 15 inches,... Elementary Course of Geometry ... - Page 5by Charles William Hackley - 1847 - 103 pagesFull view - About this book
| Mathematics - 1801 - 658 pages
...being 20, and at the less end 10 ? .Ans. 464-205. 4. How many solid feet are jn a piece of ^irrtber, whose bases are squares, each side of the greater...15 inches, and each side of the less end 6 inches j also the length, or perpendicular altitude, is 24 feet ?_ Ans. 5. To find the content of the frustum... | |
| Charles Hutton - Mathematics - 1807 - 464 pages
...circumferences j then taking one-third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece...inches ; also, the length or perpendicular altitude 2-1 feet. Ans. 19.£. Ex. 2. Required the content of a pentagonal frustum, •whose height is 5 feet,... | |
| Samuel Webber - Mathematics - 1808 - 520 pages
...circumference at the greater end being 2O, and at the less end 10 ? Ans. 464*205. 4. How many solid feet are in a piece of timber, whose bases are squares, each...inches ; also the length, or perpendicular altitude, is 24 feet ? Ans. 5. To find the content of the frustum of a cone, the altitude being 18, the greatest... | |
| Charles Hutton - Mathematics - 1811 - 442 pages
...circumferences ; then taking one-third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece...side of the less end 6 inches ; also, the length or the perpendicular altitude 24 feet. Ans. 19{.Ex. 2. Required the content of a pentagonal frustrum,... | |
| Charles Hutton - Mathematics - 1812 - 620 pages
...the circumferences; then taking one-third of the product, to multiply by the length, for the content. Ex. 1 . To find the number of solid feet in a piece of timber, whose bases arc squares, each side of the greater end being 1 5 inches, and each side of the less end 6 inches... | |
| Charles Hutton - Mathematics - 1816 - 610 pages
...circumferences ; then taking one-third of the product to multiply 1)) the length, for the content. Ex 1. To find the number of solid feet in a piece...15 inches, and each side of the less end 6 inches ; afso, the Jength or perpendicular altitude 24 fee{. . Ans. 19J. Ex. 2. Required the content of a... | |
| Charles Hutton - Arithmetic - 1818 - 646 pages
...circumferences ; then taking one- third of the product to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece...bases are squares, each side of the greater end being 16 inches, and each side of the less end 6 inches ; also, the length or perpendicular altitude 24 feet.... | |
| Charles Hutton - Mathematics - 1822 - 616 pages
...the content. E*. 1. To find the nnmber of solid feet in a piece of timfcer. whose bases are- square*, each side of the greater end being 15 inches, and...the length or perpendicular altitude 24 feet. Ans. U'! Ex. 2. Required the content of a pentagonal frustum, whose height is 6 leet, each side of the base... | |
| Charles Hutton - Mathematics - 1825 - 608 pages
...taking one-ihird of the product to multiply by the length, for the content. Ex. 1. To find the numbej of solid feet in a piece of timber, whose bases are...the length or perpendicular altitude 24 feet. Ans. !«£ Ex. Z. Required the content of a pentagonal frustum, whose height is 6 feet, each side of the... | |
| Charles Hutton - Mathematics - 1831 - 632 pages
...circumferences ; then taking one. third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece...side of the less end 6 inches ; also, the length or the perpendicular allitude 24 feet. Ans. 19i. Ex. 2. Required the content of a pentagonal frustum,... | |
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