| sir John Frederick W. Herschel (1st bart.) - 1833 - 500 pages
...shall exemplify its application in numbers. Now, it appears by observation, that two points, each ten feet above the surface, cease to be visible from each other over still water, and in average atmospheric circumstances, at a distance of about 8 miles. But 1 0 feet is the 528th... | |
| Sir John Frederick William Herschel - Astronomy - 1833 - 444 pages
...shall exemplify its application in numbers. Now, it appears by observation, that two points, each ten feet above the surface, cease to be visible from each other over still water, and in average atmospheric circumstances, at a distance of about 8 miles. But 1 0 feet is the 528th... | |
| William Benjamin Carpenter - 1843 - 290 pages
...as that distance does to the height of the eye above the sea-level. Now it appears by observation, that two points, each 10^ feet above the surface,...from each other, over still water, at a distance of about eight miles. As the interruption is caused by the convexity or bulging of the water half-way... | |
| William Benjamin Carpenter - Astronomy - 1843 - 604 pages
...height of the eye above the sea-level. Now it appears by observation, that two points, each l0jfeet above the surface, cease to be visible from each other, over still water, at a distance of about eight miles. As the interruption is caused by the convexity or bulging of the water half-way... | |
| William Benjamin Carpenter - Astronomy - 1844 - 604 pages
...as that distance does to the height of the eye above the sea-level. Now it appears by observation, that two points, each 10^ feet above the surface,...from each other, over still water, at a distance of about eight miles. As the interruption is caused by the convexity or bulging of the water half-way... | |
| John Frederick William Herschel - Astronomy - 1849 - 672 pages
...shall exemplify its application in numbers. Now, it appears by observation, that two points, each ten feet above the surface, cease to be visible from each other over still water, and in average atmospheric circumstances, at a distance of about 8 miles. But 10 feet is the 528th... | |
| Alfred Wrigley - 1852 - 344 pages
...what is the height of the mountain ? 249. Having given that two points, each 10 feet above the earth,s surface, cease to be visible from each other over still water at a distance of 8 miles ; find the earth,s diameter. 250. What is the dip of the horizon from the top of a mountain 1|- miles high, the... | |
| John Frederick William Herschel - Astronomy - 1853 - 608 pages
...shall exemplify its application in numbers. Now, it appears by observation, that two points, each ten feet above the surface, cease to be visible from each other over stiH water, and in average atmospheric circumstances, at a distance of abo»t 8 miles. But 10 feet... | |
| Alfred Wrigley - 1857 - 332 pages
...what is the height of the mountain ? 28. Having given that two points, each 10 feet above the earth,s surface, cease to be visible from each other over still water at a distance of 8 m1les ; find the earth,s diameter. 29. What 1s the dip of the horizon from the top of a mountain 1|-... | |
| John Hymers - Logarithms - 1858 - 292 pages
...subtends at the Moon being 57'. 1",8, the Moon's distance = 60,2796 times the Earth's ra- ¡ ||* dins. 52. Having given that two points, each 10 feet above the...miles, and AE = 10 feet = - — — — miles. Let С be о X 1760 x .. the Earth's center, and CD = r, then AE . (2r + AE) = AIT, or 2r . r — 7=7^; =... | |
| |