 | Denison Olmsted - Astronomy - 1839 - 306 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
 | Denison Olmsted - Astronomy - 1839 - 504 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the sdjaeent extremes, or of the cosines of the opposite extremes. (The corresponding vowels arc marked... | |
 | Denison Olmsted - Astronomy - 1839 - 304 pages
...the middle part, the opposite parts are a and B. Napier's rule is as follow* : Radius into the fine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
 | Anthony Dumond Stanley - Geometry - 1848 - 134 pages
...next to this and separated by it are called the adjacent parts, and the other two the opposite parts. The SINE of the MIDDLE part, equals the product of the TANGENTS of the ADJACENT parts, and equals the product of the COSINES of the OPPOSITE parts. This proposition may be more easily remembered,... | |
 | William Somerville Orr - Science - 1854 - 534 pages
...then it will be found that all the formulas of the last article are included in the following rule. " The sine of the middle part equals the product of the tangents of the adjacent parts, and also equals the product of the cosines of the opposite parts ; " Or, Sin. mid. = tan. ad. = cos.... | |
 | Edward Olney - Trigonometry - 1885 - 222 pages
...cos DOE, or cos a = cos 6 cos e- (5) 119- Rule 2- Prop- — In any right angled spherical triangle, the sine of the middle part equals the product of the tangents of the adjacent extremesDEM — In the spherical triangle BАC, right angled at A, taking b, e, comp B, comp C, and... | |
 | Edward Olney - Geometry - 1872 - 562 pages
...cos DOE, or cos a = cos b cos e. (5) 1 19- Rule 2. Prop, — In any right angled spherical triangle, the sine of the middle part equals the product of the tangents of the adjacent extremes, SPHERICAL TRIGONOMETRY. sin b = tan '• x tan (comp C), or sin 6 = tan e cot C ; (1) sin... | |
 | Edward Olney - Trigonometry - 1872 - 216 pages
...cos DOE, or cos а = cos b cos c (6) 1 19. Rule 2. Prop. — In any right angled spherical triangle, the sine of the middle part equals the product of the tangents of the adjacent extremes. DEM.— In the spherical triangle ВАС, right angled at A, taking b, e, comp B, comp C,... | |
 | Edward Olney - Geometry - 1872 - 472 pages
...cos DOE, or cos a = cos i cos e. (5) 119. Rule 2. Prop. — In any right angled spherical triangle, the sine of the middle part equals the product of the tangents of the adjacent extremes. DEM.— In the spherical triangle BAC, right angled at A, taking b, c, comp B, comp C, and... | |
 | Simon Newcomb - Trigonometry - 1882 - 372 pages
...parts. In the seoond case the adjoining parts are called opposite parts. 111. Napier's rules are : I. The sine of the middle part equals the product of the tangents of the adjacent parts. II. The sine of the middle part equals the product of the cosines of the opposite parts. The concurrence... | |
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Rules are . (1) The sine of the middle part equals the product of the tangents of the adjacent parts. 
