A Treatise on Plane and Spherical Trigonometry |
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Page vii
... c . Waring's property of chords ; Vieta's ......... 53 De Moivre's formula ..... .......... .... Cotes's Resolution of a Trinomial . ....... ..... 57 58 , & c . Table of Contents . iii Page Expressions for the powers ii Table of Contents .
... c . Waring's property of chords ; Vieta's ......... 53 De Moivre's formula ..... .......... .... Cotes's Resolution of a Trinomial . ....... ..... 57 58 , & c . Table of Contents . iii Page Expressions for the powers ii Table of Contents .
Page vii
... spherical triangle .... 188 Legendre's theorem for solving spherical triangles that are nearly plane . 191 Reduction of spherical to angles contained by the chords 194 Table of Contents . CHAP . XIII . Theory of iv Table of Contents .
... spherical triangle .... 188 Legendre's theorem for solving spherical triangles that are nearly plane . 191 Reduction of spherical to angles contained by the chords 194 Table of Contents . CHAP . XIII . Theory of iv Table of Contents .
Page 4
... chord of AB : as Bgb , bfb ' ( see fig . p . 7. ) are the chords of the arcs BQb , bab ' . The complement of AB is ( l . 15. ) BQ , since AB + BQ = quadrant : now BQ being considered as the arc of which 4 Definition of sine; sine of an ...
... chord of AB : as Bgb , bfb ' ( see fig . p . 7. ) are the chords of the arcs BQb , bab ' . The complement of AB is ( l . 15. ) BQ , since AB + BQ = quadrant : now BQ being considered as the arc of which 4 Definition of sine; sine of an ...
Page 10
... chord ( An B ) , therefore , of an arc A is double the sine ( An ) of half the arc : or , which is the same proposition , the ( ) : 2 sine of an arc ( A ) is half the chord of twice that arc ( 2 A ) . Instead of making A = the arc AB ...
... chord ( An B ) , therefore , of an arc A is double the sine ( An ) of half the arc : or , which is the same proposition , the ( ) : 2 sine of an arc ( A ) is half the chord of twice that arc ( 2 A ) . Instead of making A = the arc AB ...
Page 20
... chord of 60 ° ) = radius CA = 1 , and , BF sin . 30 ° = ( see Art . 10 . ) = 112 BB ' = 1 112 = .5 , and ... cos . 30 ° or sin . 60 ° √ ( 1-1 ) == . 8660254 , and ( see p . 8660.254 to a radius = 10,000 , and 8660254 to a radius ...
... chord of 60 ° ) = radius CA = 1 , and , BF sin . 30 ° = ( see Art . 10 . ) = 112 BB ' = 1 112 = .5 , and ... cos . 30 ° or sin . 60 ° √ ( 1-1 ) == . 8660254 , and ( see p . 8660.254 to a radius = 10,000 , and 8660254 to a radius ...
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1+cos A.cos a+b+c ABDE Acad ANMB arithmetical Astron Astronomy chord circle circumference co-sec co-tan consequently cubic equations deduced determined difference equal equation Euclid Example formula fraction given Hence included angle instance Introduction to Taylor's latter loga logarithmic tangents method of solution multiple arcs multiply negative oblique-angled triangles obtained plane pole preceding methods Prob Problem Prop Proposition quadrant quadratic equation quantity radius registered computations required to express result right angle right ascension right-angled spherical triangles rithms root secant Sherwin's Tables shew similar similarly sin.c sine sine and cosine sphere spherical angle spherical excess Spherical Trigonometry substitute subtract supplemental triangle surface Theorem Third Method Trigonometrical formulæ Trigonometrical Tables versed sine versin
Popular passages
Page 191 - The surface of a spherical triangle is measured by the excess of the sum of its three angles above two right angles, multiplied by the tri-rectangular triangle.
Page 126 - THEOREM. Every section of a sphere, made by a plane, is a circle.
Page 127 - The sum of the three sides of a spherical triangle is less than the circumference of a great circle. Let ABC be any spherical triangle; produce the sides AB, AU, till they meet again in D.
Page 142 - That is, the sines of the sides of a spherical triangle are proportional to the sines of the opposite angles.
Page 125 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 171 - B . sin c = sin b . sin C cos a = cos b . cos c + sin b . sin c cos b = cos a . cos c + sin a . sin c cos A cos B cos c = cos a . cos b + sin a . sin b . cos C ..2), cotg b . sin c = cos G.
Page 25 - It depends on the principle, that the difference of the squares of two quantities is equal to the product of the sum and difference of the quantities.
Page 138 - ... sun in the meridian. The arches being supposed semi-circular, it is required to find the curve terminating that part of the surface of the water which is illuminated by the sun's rays passing through any arch. 7- It is required to express the cosine of an angle of a spherical triangle in terms of the sines and cosines of the sides.
Page 134 - The measure of the surface of a spherical triangle is the difference between the sum of its three angles and two right angles.
Page 188 - From the logarithm of the area of the triangle, taken as a plane one, in feet, subtract the constant log 9-3267737, then the remainder is the logarithm of the excess above 180°, in seconds nearly.* 3.