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" Given two sides, and an angle opposite one of them, to find the remaining parts. 19. For this case, we employ proportions (3); sin a : sin b : : sin A .Ex. 1. Given the side a = 44° 13• 45", b = 84° 14• 29", and the angle A = 32° 26• 07" : required... "
An Elementary Treatise of Spherical Geometry and Trigonometry - Page 74
by Anthony Dumond Stanley - 1848 - 122 pages
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Mathematical and Astronomical Tables: For the Use of Students in Mathematics ...

William Galbraith - Astronomy - 1834 - 454 pages
...equal to 92° 46', it will cut AB in B forming the triangle ABC which was Ac JJ required. 6. Given two sides, and an angle opposite one of them, to find the other angles and the third side. In the triangle ABC are given the side AB 274, AC 306, and the angle B 78°...
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Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1836 - 394 pages
...given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the re maining parts. For this case we employ equation (1.) ; As sin a : sin b : : sin A : sin B. Ex. 1....
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An elementary course of practical mathematics, Part 3

James Elliot - 1851 - 162 pages
...63° 55' + , or 116° 5'- ; and 67° 38'-, or 15° 28' ±. PROBLEM IV. In any Triangle, having given two Sides and an Angle opposite one of them, to find the third Side. RULE. Find the angles by Problem in, and then the third side by Problem n. NOTE. When the...
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Elements of Geometry and Trigonometry

Adrien Marie Legendre - Geometry - 1852 - 436 pages
...given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the remaining parts. 19. For this case, we employ equations (3) ; sin a : sin & : : sin A Ex. 1. Given...
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Annual Report of the Trustees, Volumes 4-8

1853 - 476 pages
...sides opposite. 11. In a spherical triangle, find sin J A. 12. Given two sides of a spherical triangle, and an angle opposite one of them, to find the other parts. 13. Prove Napier's analogies. 14. Given a = 64° 40', and b = 42° 12' in a right angled spherical...
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Elements of Geometry and Trigonometry from the Works of A.M. Legendre ...

Charles Davies - Geometry - 1854 - 436 pages
...given two sides and the included angle. 6. Having given two angles and the included side. CASE I. Given two sides, and an angle opposite one of them, to find the remaining parts. 19. For this case, we employ proportions (3); sin a : sin b : : sin A .Ex. 1. Given...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Elias Loomis - Trigonometry - 1855 - 192 pages
...and the included side. 5. Given the three sides. • 6. Given the three angles. CASE I. (219.) Given two sides and an angle opposite one of them, to find the remaining parts. by Theorem III. ^/ \ In the triangle ABC, let there be given the two sides AC and...
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Tables of Logarithms of Numbers and of Sines and Tangents for Every Ten ...

Elias Loomis - Logarithms - 1859 - 372 pages
...angles and the included side. 5. Given the three sides. 6. Given the three angles. CASE I. (219.) Given two sides and an angle opposite one of them, to find the remaining parts. In the triangle ABC, let there be given the two sides AC and BC, and the angle A opposite...
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Plane and Solid Geometry: To which is Added Plane and Spherical Trigonometry ...

George Roberts Perkins - Geometry - 1860 - 472 pages
...the last significant figure on the right, which must be subtracted from 10. (§ 32.) CASR 1I. Given, two sides and an angle opposite one of them, to find the other parU. e _B Suppose the sides a and 5 to be given, and the angle A opposite the side a. By Theorem I.,...
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Treatise on Geometry and Trigonometry: For Colleges, Schools and Private ...

Eli Todd Tappan - Geometry - 1868 - 444 pages
...Then find the remaining sides by the formula (867), sin. A : sin. B : : a : b. 872. Problem — Given two sides and an angle opposite one of them, to find the other angles and side. Find the angle opposite the other given side by the formula, a : b : : sin. A : sin....
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