An Elementary Treatise on Geometry: Simplified for Beginners Not Versed in Algebra. Part II, Containing Solid Geometry, with Its Application to the Solution of Problems |
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Page 34
... multiplying 5 × 2 × 21 ; the product of 5 by 2 is 10 , and 10 by 21 is 25 ; which is the answer which we obtained in the first place . Remark . Multiplying the three dimensions of a parallelo- piped is the same as multiplying its basis by ...
... multiplying 5 × 2 × 21 ; the product of 5 by 2 is 10 , and 10 by 21 is 25 ; which is the answer which we obtained in the first place . Remark . Multiplying the three dimensions of a parallelo- piped is the same as multiplying its basis by ...
Page 35
... Its Application to the Solution of Problems Francis Joseph Grund. QUERY III . From the manner in which the solidities ... bases multiplied by their heights ; because these products are their solidities expressed in cubic measure . Thus ...
... Its Application to the Solution of Problems Francis Joseph Grund. QUERY III . From the manner in which the solidities ... bases multiplied by their heights ; because these products are their solidities expressed in cubic measure . Thus ...
Page 36
... Its Application to the Solution of Problems Francis Joseph Grund. In like ... multiplied twice by itself , you may write AB3 , which signifies the same ... bases , that is , if AB × BC were equal to abbc , could you not find a more simple ...
... Its Application to the Solution of Problems Francis Joseph Grund. In like ... multiplied twice by itself , you may write AB3 , which signifies the same ... bases , that is , if AB × BC were equal to abbc , could you not find a more simple ...
Page 40
... basis and height . 2. The solidity of an oblique parallelopiped is found like that of a right parallelopiped by multiplying its basis by its height ; because the solidity of a right parallelopiped of the same basis and height , to which it ...
... basis and height . 2. The solidity of an oblique parallelopiped is found like that of a right parallelopiped by multiplying its basis by its height ; because the solidity of a right parallelopiped of the same basis and height , to which it ...
Page 43
... multiplying its basis by its height . Thus , the cubic contents of the prism ABCEFG is equal to the area of the basis ABC , expressed in square feet , inches , & c , multiplied by the neight AE expressed in feet , inches , & c . For the ...
... multiplying its basis by its height . Thus , the cubic contents of the prism ABCEFG is equal to the area of the basis ABC , expressed in square feet , inches , & c , multiplied by the neight AE expressed in feet , inches , & c . For the ...
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Common terms and phrases
ABCDEF arcs axis basis ABC basis and height bodies calculate called CAVSAS centre cone ABC consequently convex surface corresponding sides cube root cubic contents cubic feet cubic inches diameter distance divided DOCERE draw equal and parallel equal bases equal heights find the solidity foot found by multiplying frustrum GEORGIA LIBRARIES inferences logarithms lower basis manner mean proportional multiplying its basis oblique parallelopiped paral parallel circles parallel planes perpendicular plane angles Plane Geometry plane MN plane parallel polygon PROBLEM prove pyra pyramid ABCD pyramids of equal QUERY radii radius ramid ratio Remark RERVM right angles right cone right cylinder right parallelopiped right prism similar solid angle Solid Geometry SOLUTION spherical spherical angle square feet straight line third three pyramids tiplying triangle AGC triangular prism triangular pyramid truncated prism ungula UNIVERSITY OF GEORGIA upper basis vertex vertices whole pyramid zone