 | Roswell Chamberlain Smith - 1814 - 300 pages
...the Extremes and Ratio are ciren, to find Oí* Sum of the Series, we /tare tin: following easy RULE. Multiply the last term, by the ratio, from the product...subtract the first term, and divide the remainder by (he ratio, less 1 ; the quotient will be the sum of the eerie« required. « 9. If the extrem« be... | |
 | Arithmetic - 1817 - 214 pages
...terms given, which, being multiplied by the first term, will give the last term, or greater ex treats. 2 Multiply the last term by the ratio, from the product...the first term, and divide the remainder by ratio Jess (?ae for the sum of the series. EXAMPLE?. 1. A thresher wrought 20 da}-s, and received for the... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...which the series is increased or decreased is called the ratio. The last term and sum of the series are found by this RULE. 1. Raise the ratio to the power...thresher wrought 20 days, and received for the first days labour 4 grains of wheat; for the second, 12; for the third, 36, &c. How much did his wages amount... | |
 | Zachariah Jess - Arithmetic - 1824 - 224 pages
...of terms given, which multiply by the first term, that product is the last -term or greater extreme. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio lessjone; the quotient will be the sum of the series. EXAMPLES. I Sold 24 yards of Holland,... | |
 | Thomas Tucker Smiley - Arithmetic - 1825 - 224 pages
...of terms given. 2. Multiply the product by the first term and that product will be the last term. 3. Multiply the last term by the ratio, from the product subtract the first term and divide the remain, tier by the ratio less one, for the sum of the series. Questions. What is Geometrical Progression... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...right hand must remain the game as in the geometrical term. Then to find the sum of all the terms, multiply the last term by the ratio ; from the product,...subtract the first term, and divide the remainder by the ratio, less one ; the quotient will be the sum of all the terms. Or shorter t thus : Involve the... | |
 | Arithmetic - 1831 - 198 pages
...than the number of terms given, which, being multiplied by the first term, will give the last terfln, or greater extreme. 2. Multiply the last term by the...wrought 20 days, and received for the first day's labour 4 grains of wheat; for the second, 12: for the third, 36, &c. How much did his wages amount... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...when the extremes and ratio are given, to find the sum of the series, we have the following easy HULE. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. ft If the extremes be 5 and... | |
 | Stephen Pike - Arithmetic - 1835 - 210 pages
...and sum 01' the series are found by this RULE. 1. Raise the ratio to the power whose index is one is than the number of terms given, which, being multiplied...1. A thresher wrought 20 days, and received for the Irst day's labour 4 grains of wheat; for the second, 12; ror the third, 36, &c. How much did his wages... | |
 | Charles Potts - Arithmetic - 1835 - 202 pages
...lessll than the number of terms given, and multiply it by the first | term, will give the last term. 2. Multiply the last term by the ratio, from the product...subtract the first term, and divide the remainder by the ratio less 1, for the sum of the series. EXAMPLES. 1. A labourer wrought 20 days, and received... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio less one for the sum of the series. 
