 | Chemistry - 1897 - 598 pages
...resistance. The exact value of this loss is given by the expressions: Watts lost= 72 R=EI = -^R in which / is the current in amperes, R is the resistance in ohms, and E is the drop or lost pressure in volts, being applicable either to the whole circuit or to any part... | |
 | 1900 - 594 pages
...external resistance. Ans. (20) We here use formula 16,./= C' Rt, where /is the work in joules, £7 is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this case, C= 14.2 amperes, R = 8 ohms, / = 4,500 seconds. Then, the work... | |
 | International Correspondence Schools - Coal mines and mining - 1900 - 704 pages
...external resistance. Ans. (20) We here use formula 16, ./ = C' R /.where /is the work in joules, C is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this case, C= 14.2 amperes, A' = 8 ohms, / = 4,500 seconds. Then, the... | |
 | International Correspondence Schools - Electric lighting - 1901 - 630 pages
...22.7421 am/ lo,200 peres. Ans. • (16) By formula 16, /= C' R t, where / is the work done in joules, C is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this example, C = 2.4 amperes, R = 45 ohms, t — 3,000 seconds. Then... | |
 | Francis Bacon Crocker - Electric lighting - 1901 - 514 pages
...The exact value of this loss is given by the expressions: — Watts lost = /2y?= EI= *^R in which / is the current in amperes, R is the resistance in ohms, and E is the drop or lost pressure in volts, being applicable either to the whole circuit or to any part... | |
 | Engineering - 1902 - 524 pages
...7421 am* 1 U | iC\)\i peres. Ans. (16) By formula 16, /= C' R t, where / is the work done in joules, C is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this example, C '= 2. 4 amperes, R = 45 ohms, / = 3,000 seconds. Then... | |
 | International Correspondence Schools - Arithmetic - 1904 - 656 pages
...22.7421 am. * J. O j vUw peres. Ans. (16) By formula 16,y=6"' R t, where / is the work done in joules, C is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this example, C — 2. 4 amperes, R = 45 ohms, / = 3,000 seconds. Then... | |
 | Benjamin Warner Snow - Physics - 1921 - 852 pages
...expressed in amperes. E is the electromotive force, or difference of potential, measured in volts, R is the resistance in ohms, and t is the time in seconds. These are the relations that are always used in calculating the quantity of heat developed in a conductor... | |
 | Paul F. Lurquin - Science - 2001 - 202 pages
...square wave pulse, the energy is 137 W = Vit = I2Rt = (V2/R)t, where V is the set voltage in volts, Í is the current in amperes, R is the resistance in ohms, and i is pulse time in seconds. To calculate EDV, W is divided by the volume of the protoplast suspension.... | |
 | Aeronautics - 1966 - 872 pages
...less heat, according to the relationship H<* I2 Rt, where H is the energy r heat) in watt-seconds, I is the current in amperes, R is the resistance in ohms, and t the time in seconds. A proportionality constant K can be inserted to convert this relationship the... | |
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C is the current in amperes, R is the resistance in ohms, and / is the time in seconds. In this example, C = 2.4 amperes, R = 45 ohms, t — 3,000 seconds. 