 The product of two sides of a triangle is equal to the product of the diameter of the circumscribed circle and the altitude upon the third side.  Elements of Geometry - Page 147by Andrew Wheeler Phillips, Irving Fisher - 1896 - 540 pagesFull view - About this book
 | Frederick Augustus Griffiths - 1839 - 348 pages
...any triangle taken together are equal to two right angles, or 180°. The difference of the squares of two sides of a triangle is equal to the product of their sum and difference. The sides of a triangle are proportional to the sines of their opposite angles.... | |
 | Frederick Augustus Griffiths - Artillery - 1859 - 426 pages
...any triangle, taken together, are equal to two right angles, or 180°. The difference of the squares of two sides of a triangle is equal to the product of their sum, and difference. The sides of a triangle are proportional to the sines of their opposite... | |
 | William Chauvenet - Geometry - 1871 - 380 pages
...the distance EF is zero. PROPOSITION XX.— THEOREM. 65. In any triangle, the product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the tidrd side from the vertex of the opposite angle. Let AB, AC,... | |
 | William Chauvenet - Mathematics - 1872 - 382 pages
...the distance EF is zero. PROPOSITION XX.— THEOREM. 65. In any triangle, the product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the tiiird side from the vertex of the opposite angle. Let AB, AC,... | |
 | John Reynell Morell - 1875 - 220 pages
...that the area of the triangle made by it with the sides of that angle is equal to a given square. 173. The product of two sides of a triangle is equal to the product of the height perpendicular to the third side, by the diameter of the circumscribed circle. 174. Divide a... | |
 | 1876 - 646 pages
...distance from the foot of the perpendicular. Corollaries. 2. In any triangle the product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the third side from the vertex of the opposite angle. 3. Two sides... | |
 | George Albert Wentworth - Geometry - 1877 - 416 pages
...EDXAD, then BAX AC = BDX DC+Tl?. PROPOSITION XIX. THEOREM. 300. In any triangle ihe product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the third side from the vertex of the opposite angle. Let ABC be... | |
 | George Albert Wentworth - Geometry, Modern - 1881 - 266 pages
...AC = BD XD С + AD\ '5. ED PROPOSITION XIX. THEOREM. 300. In any triangle the product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the third side from the vertex of the opposite angle. ,- '-^ A Let... | |
 | F. B. Stevens - Examinations - 1884 - 202 pages
...distance from the foot of the perpendicular. Corollaries. 2. Ju any triangle the product of two sides is equal to the product of the diameter of the circumscribed circle by the perpendicular let fall upon the third side from the vertex of the opposite angle. 3. Two sides... | |
 | George Albert Wentworth - 1884 - 264 pages
...respectively. Prove that the triangles ABC, DEFare similar. 16. In every triangle the product of two sides is equal to the product of the diameter of the circumscribed circle andthe altitude upon the third side. If AC, BC are taken as the two sides, draw the diameter CE, and... | |
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