Elements of Geometry |
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Page 1
... intersection , A , is the vertex of the angle ; the lines AB , AC , are its sides . An angle is sometimes denoted simply by the letter at the ver- tex , as A ; sometimes by three letters , as BAC or CAB , the letter at the vertex always ...
... intersection , A , is the vertex of the angle ; the lines AB , AC , are its sides . An angle is sometimes denoted simply by the letter at the ver- tex , as A ; sometimes by three letters , as BAC or CAB , the letter at the vertex always ...
Page 7
... ; whence the point D , which must be at the same time in the lines BA and CA , can only be at their intersection A ; therefore the two triangles ABC , Fig . 23 . Fig . 24 . Fig . Of Perpendicular and Oblique Lines . 7.
... ; whence the point D , which must be at the same time in the lines BA and CA , can only be at their intersection A ; therefore the two triangles ABC , Fig . 23 . Fig . 24 . Fig . Of Perpendicular and Oblique Lines . 7.
Page 18
... intersection from the fixed point F , is not exactly double the distance of the preceding point of intersection ; since FN , for example , is less than FM + MN , or 2 FM ; we have , in like manner , FP < 2 FN , FQ < 2 FP , & c . But ...
... intersection from the fixed point F , is not exactly double the distance of the preceding point of intersection ; since FN , for example , is less than FM + MN , or 2 FM ; we have , in like manner , FP < 2 FN , FQ < 2 FP , & c . But ...
Page 30
... intersection , and will bisect it . Demonstration . The line AB ( fig . 57 , 58 ) , which joins the points of intersection , is a chord common to the two circles ; and , if a perpendicular be erected upon the middle of this chord , it ...
... intersection , and will bisect it . Demonstration . The line AB ( fig . 57 , 58 ) , which joins the points of intersection , is a chord common to the two circles ; and , if a perpendicular be erected upon the middle of this chord , it ...
Page 31
... intersection may take place , the triangle ACD ( fig . 57 , 58 ) must be possible . It is necessary , then , not only that CD ( fig . 57 ) should be less than AC + AD , but also that the greater radius AD ( fig . 58 ) should be less ...
... intersection may take place , the triangle ACD ( fig . 57 , 58 ) must be possible . It is necessary , then , not only that CD ( fig . 57 ) should be less than AC + AD , but also that the greater radius AD ( fig . 58 ) should be less ...
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Common terms and phrases
ABC fig adjacent angles altitude angle ACB angle BAC base ABCD bisect centre chord circ circular sector circumference circumscribed common cone consequently construction convex surface Corollary cube cylinder Demonstration diagonals diameter draw drawn equal angles equiangular equilateral equivalent faces figure formed four right angles frustum GEOM given point gles greater hence homologous sides hypothenuse inclination intersection isosceles triangle join less Let ABC let fall Let us suppose line AC mean proportional measure the half meet multiplied number of sides oblique lines opposite parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism produced proposition radii radius ratio rectangle regular polygon right angles Scholium sector segment semicircle semicircumference side BC similar solid angle sphere spherical polygons spherical triangle square described straight line tangent THEOREM third three angles triangle ABC triangular prism triangular pyramids vertex vertices whence
Popular passages
Page 67 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Page 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 65 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Page 160 - ABC (fig. 224) be any spherical triangle ; produce the sides AB, AC, till they meet again in D. The arcs ABD, ACD, will be...
Page 168 - In any spherical triangle, the greater side is opposite the greater angle ; and conversely, the greater angle is opposite the greater side.
Page 157 - CIRCLE is a plane figure bounded by a curved line, all the points of which are equally distant from a point within called the centre; as the figure ADB E.
Page 8 - Any side of a triangle is less than the sum of the other two sides...
Page 82 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Page 29 - Two equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre.
Page 182 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.