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" Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer... "
Cobb's Explanatory Arithmetick, Number Two: Containing the Compound Rules ... - Page 168
by Lyman Cobb - 1835 - 216 pages
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - Surveying - 1811 - 580 pages
...greater, or less than the first, then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer ; — in the same denomination with the third term. EXAMPLES. If 3 acres .3 roods of land can be purchased...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ...

Nathan Daboll - Arithmetic - 1813 - 244 pages
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and...the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - Surveying - 1814 - 558 pages
...greater, or less than the first, then multiply the second and third ternis together, and divide the product by the first term/ and the quotient will be the answer ; — in the same denomination with the third term. EXAMPLES. If 3 acres 3 roods of land can be purchased...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - Arithmetic - 1815 - 250 pages
...terms to the same denomination, aiid reduce the second term to the lowest name ir.antioned in it. 3. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the answer to the question, in the same denomination you left the second term...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - Arithmetic - 1818 - 246 pages
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term, the quotient will be the answer to the question, in fue same denomination you left the second term...
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Arithmetic Modernised: Or, A Complete System of Arithmetic, Adapted to ...

John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, multiply the second and third terms together, and divide their product by thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc...
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A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - Arithmetic - 1822 - 436 pages
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then multiply the second and third terms together, and divide their product by the first, ami the quotient gives the answer ; which is always of the same name with the middle term. When the...
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A Treatise on Practical Gauging

Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...parts of their integer ; multiply the second and third terms of the proportion together, and divide the product by the first term, and the quotient- will be the answer required, which must, if necessary, be reduced to its integral value. Note 1. In solving questions...
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Elements of Arithmetic

Etienne Bézout - Mathematics - 1824 - 238 pages
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; Multiply the second and third terms together and divide their product by the first ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the...
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The tutor's expeditious assistant; being a system of practical arithmetic ...

John White - Arithmetic - 1826 - 128 pages
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. Multiply the second and third terms together, and divide their product by the first, and their quotient will be the answer, in the same denomination as that in which the second was left....
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