Elements of Geometry and Trigonometry |
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Page 93
... ALTITUDE OF A TRIANGLE , is the perpendicular distance from the vertex of either an- gle to the opposite side , or ... base of the triangle . 5. The ALTITUDE OF dicular distance between sides . A BOOK IV Proportions of Figures ...
... ALTITUDE OF A TRIANGLE , is the perpendicular distance from the vertex of either an- gle to the opposite side , or ... base of the triangle . 5. The ALTITUDE OF dicular distance between sides . A BOOK IV Proportions of Figures ...
Page 94
... base . I 6. The ALTITUDE OF A TRAPEZOID , is the perpendicular distance between its parallel sides . These sides are called bases ; one the upper , and the other , the lower base . 7. The AREA OF A SURFACE , is its numerical value ...
... base . I 6. The ALTITUDE OF A TRAPEZOID , is the perpendicular distance between its parallel sides . These sides are called bases ; one the upper , and the other , the lower base . 7. The AREA OF A SURFACE , is its numerical value ...
Page 95
... base and an equal altitude . Let the triangle ABC , and the parallelogram ABFD , have equal bases and equal altitudes : then will the triangle be equal to one - half of the parallelogram . For , let them be so placed that the base of ...
... base and an equal altitude . Let the triangle ABC , and the parallelogram ABFD , have equal bases and equal altitudes : then will the triangle be equal to one - half of the parallelogram . For , let them be so placed that the base of ...
Page 99
... base and altitude ; that is , the number of superficial units in the rectangle , is equal to the product of the number of linear units in its base by the number of linear units in its altitude . Scholium 2. The product of two lines is ...
... base and altitude ; that is , the number of superficial units in the rectangle , is equal to the product of the number of linear units in its base by the number of linear units in its altitude . Scholium 2. The product of two lines is ...
Page 100
... base and altitude . Let ABC be a triangle , BC its base , and AD its altitude : then will its area be equal to BC × AD . For , from C , draw CE parallel to BA , and from A , draw AE parallel to CB . The area of the parallelogram BCEA is ...
... base and altitude . Let ABC be a triangle , BC its base , and AD its altitude : then will its area be equal to BC × AD . For , from C , draw CE parallel to BA , and from A , draw AE parallel to CB . The area of the parallelogram BCEA is ...
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Common terms and phrases
ABCD AC² adjacent angles altitude angle ACB apothem Applying logarithms base and altitude bisect centre chord circle circumference circumscribed coincide cone consequently convex surface corresponding cosec cosine Cotang cylinder denote diagonals diameter distance divided draw drawn edges equally distant feet find the area Formula frustum given angle given line given point greater hence homologous hypothenuse included angle interior angles intersection less Let ABC log sin logarithm lower base mantissa mean proportional measured by half middle point number of sides opposite parallel parallelogram parallelopipedon perimeter perpendicular plane MN polyedral angle polyedron prism PROBLEM PROPOSITION proved pyramid quadrant radii radius rectangle regular polygons right angles right-angled triangle Scholium secant segment side BC similar sine slant height sphere spherical polygon spherical triangle square Tang tangent THEOREM triangle ABC triangular prisms triedral angle upper base vertex vertices whence