Elements of Geometry and Trigonometry |
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Page 26
... example , there will remain ( A. 5 ) , ACBC AB ; < that is , the difference between any two sides of a triangle is less than the third side . Scholium . In order that any three given lines may re present the sides of a triangle , the ...
... example , there will remain ( A. 5 ) , ACBC AB ; < that is , the difference between any two sides of a triangle is less than the third side . Scholium . In order that any three given lines may re present the sides of a triangle , the ...
Page 74
... example , that this unit is contained 7 times ACB , and 4 times in the angle DOE ACB be divided into 7 angles , by the radii & c .; and DOE into 4 angles , by the radii Oz , each equal to the unit M. Then , suppose Cm , Cn , Cp , Ox ...
... example , that this unit is contained 7 times ACB , and 4 times in the angle DOE ACB be divided into 7 angles , by the radii & c .; and DOE into 4 angles , by the radii Oz , each equal to the unit M. Then , suppose Cm , Cn , Cp , Ox ...
Page 193
... example , that AE is to AI , as 15 is to 8 . Conceive AE to be which AI will contain 8 ; divided into 15 equal parts , of through the points of division These planes will let planes be passed parallel to ABCD . divide the ...
... example , that AE is to AI , as 15 is to 8 . Conceive AE to be which AI will contain 8 ; divided into 15 equal parts , of through the points of division These planes will let planes be passed parallel to ABCD . divide the ...
Page 252
... example , let them be to each other as 5 is to 48. Divide the circumference MNPQ into 48 equal parts , be- ginning at M ; MN will contain five of these parts . Join each point M of division with the points A and B , by a quadram ; there ...
... example , let them be to each other as 5 is to 48. Divide the circumference MNPQ into 48 equal parts , be- ginning at M ; MN will contain five of these parts . Join each point M of division with the points A and B , by a quadram ; there ...
Page 9
... EXAMPLE . 1. To find the logarithm of 672887 . The characteristic is 5. Placing a decimal point after the fourth figure , the number becomes 6728.87 . The mantissa of the Togarithm of 6728 is 827886 , and the corresponding number in the ...
... EXAMPLE . 1. To find the logarithm of 672887 . The characteristic is 5. Placing a decimal point after the fourth figure , the number becomes 6728.87 . The mantissa of the Togarithm of 6728 is 827886 , and the corresponding number in the ...
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Common terms and phrases
ABCD ACē adjacent angles altitude angle ACB apothem Applying logarithms base and altitude bisect centre chord circle circumference circumscribed coincide cone consequently convex surface corresponding cosec cosine Cotang cylinder denote diagonals diameter distance divided draw drawn edges equally distant feet find the area Formula frustum given angle given line given point greater hence homologous hypothenuse included angle interior angles intersection less Let ABC log sin logarithm lower base mantissa mean proportional measured by half middle point number of sides opposite parallel parallelogram parallelopipedon perimeter perpendicular plane MN polyedral angle polyedron prism PROBLEM PROPOSITION proved pyramid quadrant radii radius rectangle regular polygons right angles right-angled triangle Scholium secant segment side BC similar sine slant height sphere spherical polygon spherical triangle square Tang tangent THEOREM triangle ABC triangular prisms triedral angle upper base vertex vertices whence