Elements of Geometry: Plane and Solid |
From inside the book
Results 1-5 of 52
Page 72
... respectively , will give the vertex of the required neutral triangle ABC ; which , of course , can be described offhand , when once the form is familiar to the eye . The neutral triangle , again , can be made the basis of the neutral ...
... respectively , will give the vertex of the required neutral triangle ABC ; which , of course , can be described offhand , when once the form is familiar to the eye . The neutral triangle , again , can be made the basis of the neutral ...
Page 75
... respectively . Draw the altitude BF to AC . = H F E D B C If PD + PE BF , as the theorem asserts , then by cutting off a part of BF equal to PE , as FG , we obtain GB = PD . We evidently can obtain the point G by * The reference is to ...
... respectively . Draw the altitude BF to AC . = H F E D B C If PD + PE BF , as the theorem asserts , then by cutting off a part of BF equal to PE , as FG , we obtain GB = PD . We evidently can obtain the point G by * The reference is to ...
Page 13
... respectively supplementary to them must be unequal . 17. For each of the two exterior angles thus formed is a right angle . 18. For each of the two exterior angles thus formed , being the supplement of an obtuse angle , must be acute ...
... respectively supplementary to them must be unequal . 17. For each of the two exterior angles thus formed is a right angle . 18. For each of the two exterior angles thus formed , being the supplement of an obtuse angle , must be acute ...
Page 14
... respectively ; etc. Or show , as in Ex . 32 , that CD = CE ; etc. 38. AG = AB ( 75 ) , GE = GB + BE = AG + 2 AG = 3 AG . 39. Join AB and produce AB to C so that AC = 2 AB . With A and B as centers , and radius equal to AC , describe ...
... respectively ; etc. Or show , as in Ex . 32 , that CD = CE ; etc. 38. AG = AB ( 75 ) , GE = GB + BE = AG + 2 AG = 3 AG . 39. Join AB and produce AB to C so that AC = 2 AB . With A and B as centers , and radius equal to AC , describe ...
Page 15
... respectively , but △ AMC > LAMB ; .. PC > PB ( 90 ) . B M D 53. At the given point make a right angle ( 95 ) and bisect it ( 81 ) . 54. From the given point P , draw a perpendicular PQ to the given line ( 92 ) , and at P draw PS ...
... respectively , but △ AMC > LAMB ; .. PC > PB ( 90 ) . B M D 53. At the given point make a right angle ( 95 ) and bisect it ( 81 ) . 54. From the given point P , draw a perpendicular PQ to the given line ( 92 ) , and at P draw PS ...
Other editions - View all
Common terms and phrases
AB² ABCD AC² AE² altitude angles formed arc BC axes of symmetry base BC² bisect bisector CD² chord circumf circumference coincide construct cutting denote describe an arc diagram for Ex diameter dihedral angles draw drawn edge EF² equal angles equilateral triangle exercises exterior angles given angle given circle given line given point Hence hypotenuse inscribed intercept intersection isosceles triangle Join AC Let AB Let ABC meet mid point par'm parallel to BC parallelogram parallelopiped pass a plane perpendicular plane passed point as required polygon prism produced Prop quadrilateral radii radius equal rectangle required locus respectively right angle right triangle segment sides straight angle straight line surface tangent theorem vertex vertical angle