 | Thomas Keith - Arithmetic - 1822 - 354 pages
...consists of yards, or feet, &c. Prop. 5. Given the area or surface of a circle to find the diameter. Rule.- Divide the area by '7854, and extract the square root of the quotient. Prop. 6. The base and perpendicular of a right angled triangle being given, to find the hypothenuse.... | |
 | Oliver Welch - Arithmetic - 1826 - 242 pages
...44 rods ? 44X44X07968=154.06688, Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — Divide the area by .7854 and extract the square root of the quotient ; the root is the diameter sought. (See application of square roo.t, case 2.) PROBLEM VII. The area... | |
 | William Ruger - Arithmetic - 1832 - 282 pages
...rods ? As 355 : 113 : : 94,248 : Ans. 30 rods. The area of a circle being given, to find the diameter. RULE. — Divide the area by ,7854 and extract the square root of the quotient; the root will be the diameter sought. Or, as 355 : 452 ::so is the area : to the square of the diameter;... | |
 | Arithmetic - 1841 - 200 pages
...44 rods? 44X44X-07953=154-0668S., Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — (!). Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. (See application of sqtare root, case.2.) PROBLEM VII. The area given... | |
 | William Ruger - Arithmetic - 1841 - 268 pages
...113 :: 94,248 : Ans. 30 rods. The area of a circle being giten, to -find the diameter. RULE.-^Divide the area by ,7854, and extract the square -root of the quotient ; the root will be the diameter sought. Or, as 355 : 452 : : so is the area : to the square of the... | |
 | W. H. CRANK - Arithmetic - 1843 - 340 pages
...required the length of the arc. Ans. 4-3625 inches. Given the area of a circle to find its diameter. RULE. — Divide the area by '7854, and extract the square root of the quotient, which will give the diameter. Ex. — (1) The area of a circle is 754.7694 feet, what is its diameter?... | |
 | Almon Ticknor - Arithmetic - 1846 - 274 pages
...of 8 cents per square foot ? Ans. D615. 81.6.432. The area of a circle given, tofind the diameter. RULE. Divide the area by .7854, and extract the square root of the quotient. 1. The area of a circle is 5 acres, 3 roods, 26 perches, required the diameter. Thus: 946.000-H .7854... | |
 | Arithmetic - 1846 - 258 pages
...44x44X-07958=154-0668S, Ans. PROBLEM VI. The area of a circle given to find the diameter. ROLE. — (') Divide the area by '7854 and extract the square root of the quotient; the root is the diameter sought. (See application of square root, case 2.) PROBLEM VII. The area given... | |
 | Daniel Adams - Arithmetic - 1849 - 142 pages
...circle 4 inches in diameter ? Ans. 16. IT 64. The area of a circle being given, to find the diameter. RULE. . Divide the area by '7854, and extract the square root of the quotient. NOTE 1 . This rule being the reverse of the rule 1F63, an analysis is deemed unnecessary. EXAMPLES... | |
 | Daniel Adams - Measurement - 1850 - 144 pages
...circle 4 inches in diameter ? Ans. 16. ^F G4L* The area of a circle being given, to find the diameter. RULE. Divide the area by '7854, and extract the square root of the quotient. NOTE 1 . This rule being the reverse of the rule ?T63j an analysis is deemed unnecessary. EXAMPLES... | |
| |
Divide the area by . 7854 and extract the square root of the quotient. 
