... plus three times the product of the square of the tens by the units, plus three times the tens by the square of the units, plus the cube of the units. Elements of Algebra - Page 214by Bourdon (M., Louis Pierre Marie) - 1839 - 324 pagesFull view - About this book
| Etienne Bézout - Mathematics - 1824 - 238 pages
...the 4 tens already found, multiplied by the units sought, plus three times the same tens multiplied by the square of the units, plus the cube of the units. AYe separate the two last figures 07 ; the part 155, which remains ut the left, contains 3 times the... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...the square of the tens by the units, three times the product of the square of the units by the tens, plus the cube of the units. This being the case, the...cube of the tens, giving at least, thousands, the three last figures to the right cannot form a part of it, the cube of the tens must therefore be found... | |
| Charles Davies - Algebra - 1835 - 378 pages
...and the units by b, we have (Art. 160), of the square of the tens by the units, plus three times the product of the tens by the square of the units, plus the cube of ike units. This being the case,_the cube of the tens, giving at least, thousands, the last three figures... | |
| Charles Davies - Algebra - 1842 - 368 pages
...the cube of a number composed of tens of the square of the tens ty the units, plus three times the product of the tens by the square of the units, plus...being the case, the cube of the tens, giving at least, tJtousands, the last three figures to the right cannot form a part of it : the cube of the tens must... | |
| Davis Wasgatt Clark - 1844 - 394 pages
...of the tens, plus three times the product of the square of the tens by the units, plus three times the tens by the square of the units, plus the cube of the units. Let it now be required to reverse the above process, and find the cube root of 91125. (40)3=64000,... | |
| Charles Davies - Algebra - 1845 - 382 pages
...units, three times the product of the tens by the square of the units, and the cube ef the units. Now, the cube of the tens, giving at least, thousands,...to the right cannot form a part of it : the cube of tens must therefore be found in the part 103 which is separated from the last three figures. The root... | |
| Davis Wasgatt Clark - Algebra - 1846 - 374 pages
...of the tens, plus three times the product of the square of the tens by the units, plus three times the tens by the square of the units, plus the cube of the units. Let it now be required to reverse the above process, and find the cube root of 91125. (40)2=64000,... | |
| James Robinson (of Boston.) - 1847 - 304 pages
...plus three times the square of the tens multiplied by the units, plus three times the tens multiplied by the square of the units, plus the cube of the units. We will now reverse the process of finding the third power of 20 + 5, and we shall obtain one of its... | |
| Daniel Leach - Arithmetic - 1851 - 280 pages
...three times the square of the tens, multiplied by the units, phis three times the tens, multiplied by the square of the units , plus the cube of the units. 1; What is the cube root of 91125 ? 91125 ( 40+5^:45 64000 3 4023= ^ 625 5425x5=z27125 2. What is the... | |
| Daniel Leach - Arithmetic - 1853 - 622 pages
...three times the square of the tens, multiplied by the units, plus three times the tens, multiplied by the square of the units, plus the cube of the units. 1. What is the cube root of 91125 ? 91125 ( 40+5=45 (40)3= 64000 3 (40)a=4800 - — 3(40X5)+52= 625... | |
| |