## The first and second books of Euclid explained to beginners, by C.P. Mason |

### From inside the book

Results 1-5 of 52

Page vii

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**given**demonstration . By setting forth explicitly and at length all that is assumed as known in the course of a ...**straight line**from a**given**position round a fixed point in the line itself . This furnishes the beginner with an ... Page 2

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**a**spot of some size . But these rude material surfaces ,**lines**, and points suggest to our minds the perfect surfaces ,**lines**, and points which we deal with in geometry . The definitions of these**given**by Euclid are entirely negative ... Page 15

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**given**finite right line to construct an equilateral triangle . * The following postulates and axioms are made use of in the construction and demonstration in this proposition : — 1. Postulate I. A**straight line**may be drawn from a**given**... Page 16

... line A C , * and C and B by the right line C B. ( Post . I. ) We thus get a △ ACB , and that this is a A such as ...

... line A C , * and C and B by the right line C B. ( Post . I. ) We thus get a △ ACB , and that this is a A such as ...

**given**point to draw a**straight line**equal to a**given**finite**straight line**. * Two points are said to be joined by ... Page 20

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**given straight lines**, to cut off a part equal to the less . To do this we must be able , - 1. From a given point to draw a straight line equal to a**given straight line**. ( Prop . II . ) 2. With a given centre , and at a given distance ...### Other editions - View all

The First and Second Books of Euclid Explained to Beginners, by C.P. Mason Euclides No preview available - 2016 |

### Common terms and phrases

A B and CD A B is equal A C and CB Æneid axiom beginner bisected centre Consequently diagonal draw a straight Edition equal in area equal respectively equal to twice equilateral Euclid exterior exterior angle Fcap figure finite right line follows formed given finite right given line given point given rectilineal given straight line gnomon greater half a right hypotenuse interior and opposite isosceles Join the points join two given Jugurtha Latin length less line A B line CD linear units lines are parallel magnitudes meeting the line opposite sides parallelogram point F proof Prop proposition prove this proposition rectangle contained right angles side A C straight line meets suppose three sides triangle unequal

### Popular passages

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