## Modern Intermediate Arithmetic |

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Modern Intermediate Arithmetic Charles Edward White,Bruce Mervellon Watson No preview available - 2016 |

### Common terms and phrases

acres amount answer apiece average barrel base bill bought bushels called cent common fractions contains corn cost decimal decimal places denominator difference dimensions Divide dividend division divisor dollar dozen Draw earn eggs entire equal Express factor feet figures Find Find the cost five floor foot four fraction gain gallons Give given hour hundred hundredths inches interest length marked Measure miles minutes month Multiply Name Oral paid piece pound PROBLEMS pupils quart quotient receive Reduce REVIEW rods sacks sell Show side sold SOLUTION square square yard STATEMENT Subtract sugar thick third thousandths week weighs wide worth Write Written yard

### Popular passages

Page 95 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints = 1 quart (qt...

Page 117 - CUBIC MEASURE 1728 cubic inches (cu. in.) = 1 cubic foot (cu. ft.) 27 cubic feet = 1 cubic yard (cu. yd.) 128 cubic feet = 1 cord (cd...

Page 103 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30| square yards — 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.

Page 213 - The area of a triangle is equal to one half 'the product of its base and altitude.

Page 98 - LINEAR MEASURE 12 inches (in.) = 1 foot (ft). 3 feet = 1 yard (yd.). 5J yards or Щ feet = 1 rod (rd.) . 320 rods = 1 mile (mi.).

Page 214 - The pile of wood in the center of this picture is 8 ft. long, 4 ft. wide, and 4 ft. high. How many cubic feet does it contain ? 128 cubic feet = 1 cord.

Page 105 - The area of a rectangle is found by multiplying its length by its breadth.

Page 211 - The area of a parallelogram is equal to the product of its base and its height: A = bx h.

Page 152 - To multiply decimals, multiply as in whole numbers and point off in the product as many decimal places as there are decimal places in both multiplicand and multiplier. Note that the " pointing off " is simply the multiplying together of the denominators.