 | John Dougall - 1810 - 734 pages
...By this process we discover that there will be 3 integers and 1 decimal in the root required ; since there are always as many figures in the root, as there are dots or periods in the cubic dividend. We now inquire what number, when cubed or multiplied twice successively... | |
 | Charles Davies - Arithmetic - 1833 - 284 pages
...last figure 1 ; then by dividing we obtain, 3, the third figure of the root. NOTE 1. There will be as many figures in the root as there are periods in the given number. NOTE 2. If the given number has not an exact root, there will be a remainder after all the periods... | |
 | Charles Davies - Arithmetic - 1838 - 292 pages
...last figure 1 ; then by dividing we obtain 3, the third figure of the root. NOTE 1 . There will be as many figures in the root as there are periods in the given number. NOTE 2. If the given number has not an exact root, there will be a remainder after all the periods... | |
 | Thomas Sherwin - Algebra - 1841 - 314 pages
...periods of two figures each. The left hand period may consist of one or two figures. There will be as many figures in the root, as there are periods in the power. Separating 127449 into periods, we see that the root must contain three figures, or hundreds,... | |
 | Charles DAVIES (LL.D.) - Arithmetic - 1843 - 348 pages
...the last figure 1 ; then dividing we obtain 3, the third figure of the root. NOTE 1. There will be as many figures in the root as there are periods in the given number. NOTE 2. If the given number has not an exact root, there will be a remainder after all the periods... | |
 | Charles Davies - Arithmetic - 1844 - 356 pages
...the last figure 1 ; then dividing we obtain 3, the third figure of the root. NOTE 1. There will be as many figures in the root as there are periods in the given number. NOTE 2. If the given number has not an exact root, there will be a remainder after all the periods... | |
 | Charles Davies - Arithmetic - 1847 - 368 pages
...doubled the last figure 1 j then dividing we obtain 3, the third figure of the root. 262. There will be as many figures in the root as there are periods in the given number. If the given number has not an exact root, there will be a remainder after all the periods are brought... | |
 | Charles Davies - Arithmetic - 1850 - 412 pages
...last figure I ; then dividing we obtain 3, the third figure of the root. 309. NOTE 1.—There will be as many figures in the root as there are periods in the given number. NOTE 2.—Jf the given number has not an exact root, there will be a remainder after all the periods... | |
 | Charles Davies - 1852 - 344 pages
...the corresponding dividend. the quotient figure is too large and must be diminished. 4. There will be as many figures in the root as there are periods in the given number. EXTRACTION OF THE SQUARE ROOT. a. What is the square root of 36729 : OPERATION. 3 67 29(191.64 + 1... | |
 | Chambers W. and R., ltd - 1854 - 152 pages
...process is completed. NoTE 1. — When there is a remainder after all the periods have been brought which are extracted from the decimals in the given...is found to be greater than the dividend, a nothing [0] must be placed in the root to express this : the next period is then brought down, and annexed... | |
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... in which case ciphers may be annexed, forming new periods, each of which will give one decimal place in the root. 2. What is the square root of 36729 ? 3 67 29(191,64+. 
