 | Charles William Hackley - Algebra - 1834 - 38 pages
...subtract from the given polynomial and divide the first term of the remainder by n times the n — 1 power of the first term of the root, and the quotient will be the fourth term of the root, and so on until all the terms of the root are found. CALCULUS OF RADICALS.... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...remainder may be expressed by two factors; thus, (10X10X3 + 10X3X5 + 5X5) 5: therefore, if we divide by three times the square of the first term of the root, plus three times the first term multiplied by the second term, plus the square of the second term,... | |
 | Charles Davies - Algebra - 1835 - 378 pages
...subtract all these products from the last remainder, and divide the first term of the result by dou. ble the first term of the root, and the quotient will be the fourth term. Then proceed in the same manner to find the other terms. EXAMPLES. 1. Extract the square... | |
 | Charles Davies - Algebra - 1839 - 264 pages
...and subtract it from the first polynomial, and then divide the first term of the remainder by double the first term of the root, and the quotient will be the third term. IV. Form the double products of the first and second terms, by the third, plus the square of the third... | |
 | Bourdon (M., Louis Pierre Marie) - Algebra - 1839 - 368 pages
...subtract all these products from the last remainder, and divide the first term of the result bi/ double the first term of the root, and the quotient will be the fourth term. Thcn proceed in the same manner to find the other terms. EXAMPLES. 1. Extract the square... | |
 | Charles Davies - Algebra - 1839 - 272 pages
...subtract all these products from the last remainder, and divide the first term of the result by double the first term of the root, and the quotient will be the fourth term. Then proceed in the same manner to find (lie other terms. EXAMPLES. 1 . Extract the square... | |
 | Frederick Emerson - Arithmetic - 1839 - 300 pages
...remainder may be expressed by two factors; thus, (10X10X3 + 10X3X5- 1-5x1) 5: therefore, if we divide by three times the square of the first term of the root, plus three times the first term multiplied by the second term, plus the square of the second term,... | |
 | Charles Davies - Algebra - 1842 - 368 pages
...and subtract it from thejlrst polynomial, and then divide the first term of the remainder by double the first term of the root, and the quotient will be the third term. IV. Form the double products of the fast and second terms, by the third, plus the square of the third;... | |
 | Charles Davies - Algebra - 1842 - 284 pages
...: this will give the first term of the root. II. Divide the second term of the polynomial by double the first term of the root, and the quotient will be the second term of the root. III. Then form the square of the two terms of the root found, and subtract... | |
 | Charles Davies - Algebra - 1845 - 382 pages
...square of this term from the given polynomial. II. Divide the first term of the remainder by twice the first term of the root, and the quotient will be the second term of the root. III. From the first remainder subtract the product of twice the first term... | |
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Divide the first term of the remainder by three times the square of the first term of the root as a trial divisor, and the quotient will be the next term of the root. 
