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" An isosceles trapezoid is a trapezoid whose non-parallel sides are equal. A pair of angles including only one of the parallel sides is called a pair of base angles. Pairs of base angles The median of a trapezoid is parallel to the bases and equal to onehalf... "
Wentworth & Hill's Exercise Manuals: Geometry - Page xiv
by George Albert Wentworth - 1884
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A Geometry for Beginners

George Anthony Hill - 1886 - 368 pages
...the others in the sides of the square. 21. Prove that the line joining the middle points of the legs of a trapezoid is parallel to the bases, and equal to half their sum. 22. Divide a line into 3^ parts. CHAPTER VI. POLYGONS. C0NTENTS. — I. Sides and Angles of a Polygon...
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Exercise Manuals, Issue 3

George Albert Wentworth - 1889 - 276 pages
...Every point in the perpendicular, erected at the middle point of a straight line, is equidistant from the ends of the line, and every point not in the perpendicular...secant into equal parts. BOOK II. THE CIRCLE. THE OIRCLE AND STRAIGHT LINES. 74. Definitions. Circumference, circle, radius, diameter, arc, chord, semi-circumference,...
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Wentworth & Hills's Exercise Manuals: Geometry, Issue 3

George Albert Wentworth - 1889 - 264 pages
...ends of a straight line determine the perpendicular through the middle point of the IvaQ.^s" ^£&- Theorem. Every p'oint in the bisector of an angle...equal parts. BOOK II. THE CIRCLE. THE CIRCLE- AND STRAIGHT LINES. 74. Definitions. Circumference, circle, radius, diameter, arc, chord, semi-circumference,...
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Plane Geometry

Edward Rutledge Robbins - Geometry, Plane - 1906 - 268 pages
...J- to AC (95). That is, MX is -L to AC at its midpoint, and AM = MC (?) (67). But AM=BM (Hyp.). 149. THEOREM. The median of a trapezoid is parallel to the bases and equal to half their sum. [This is another form of stating the theorem of 144.] 150. THEOREM The perpendiculars from the vertices...
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Plane and Solid Geometry

Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...-l. to AC (95). That is, MX is -l. to AC at its midpoint, tJtf= JfC(?) (67). But AM=BM (Hyp.). 149. THEOREM. The median of a trapezoid is parallel to the bases and equal to half their sum. [This is another form of stating the theorem of 144.] 150. THEOREM. The perpendiculars from the vertices...
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Elements of Plane Geometry

William Herschel Bruce, Claude Carr Cody (Jr.) - Geometry, Modern - 1910 - 286 pages
...is parallel to one side of a triangle and bisects one side, it bisects the third side. 180. COR. 2. The median of a trapezoid is parallel to the bases and equal to half their sum. firs \ B Proof. Let ABCD be a trapezoid and E and F the midpoints of AD and BC, respectively. Draw...
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Elements of Plane Geometry

William Herschel Bruce, Claude Carr Cody (Jr.) - Geometry, Modern - 1910 - 284 pages
...of the angles of a rectangle form a square. Ex. 49. The line joining the mid-points of the diagonals of a trapezoid is parallel to the bases and equal to half their difference. Ex. 50. The lines joining the mid-points of the opposite sides of a quadrilateral bisect...
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College Entrance Examination Papers in Plane Geometry

Geometry, Plane - 1911 - 192 pages
...more remote is the greater. 2. The straight line joining the middle points of the non-parallel sides of a trapezoid is parallel to the bases and equal to half their sum. 3. In equal circles, or in the same circle, the greater of two chords subtends the greater arc. 4....
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Plane and Solid Geometry: Suggestive Method

George Clinton Shutts - Geometry - 1912 - 392 pages
...bases. SuG. Draw a diagonal of the trapezoid. The proof is left to the student. 153. COR. The diameter of a trapezoid is parallel to the bases and equal to half their sum. SUG. 1. Through one end of the diameter draw a line parallel to the bases and use the indirect method....
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Plane Geometry

William Betz, Harrison Emmett Webb - Geometry, Modern - 1912 - 368 pages
...the trapezium already appeared in this text ? Where ? PROPOSITION XXVII. THEOREM 219. The mid-line of a trapezoid is parallel to the bases and equal to half their sum. HC Given the trapezoid ABCD, and the line EF bisecting the legs AD and BC in E and F respectively....
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