 | Warren Colburn - Arithmetic - 1824 - 292 pages
...the multiplicand. In like manner \vben the divisor is 10, 100, 1000, &c. division may be performed by cutting off as many places from the right of the dividend as there are zeros in the divisor. At 10 cents a pound, how many pounds of meat may be bought for 64 cents'? The... | |
 | Warren Colburn - Arithmetic - 1826 - 264 pages
...of the multiplicand. In like manner when the divisor is 10, 100, 1000, &c. division may be performed by cutting off as many places from the right of the dividend as there are zeros in the divisor. At 10 cents a pound, how many pounds of meat maybe.' bought for 64 cents ? The... | |
 | Warren Colburn - 1829 - 258 pages
...of the multiplicand. In like manner when the divisor is 10, 100, 1000. &c. division may be performed by cutting off as many places from. the right of the dividend as there are zeros in the divisor. At 10 cents a pound, how many pounds of meal may be bought for 64 cents ? The... | |
 | Lyman Cobb - Arithmetic - 1834 - 120 pages
...the work is done. So when you divide by 100, 1000, <kc. You have merely to cut off as many figures from the right of the dividend as there are ciphers in the divisor. The principle of this is very plain, for in Multiplication you proved that joining a cipher to the... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...lut divinor (8). aril gives MS 4.9. IV. To divide ly 10, 100, 1000, #e. RULE. Cut off as many figures from the right of the dividend, as there are ciphers in the divisor. The figures on the left of the point will be the quotient ; and those on the right the remainder. 10... | |
 | Calvin Tracy - Arithmetic - 1842 - 306 pages
...97, and 2 rem. NOTE 4.— When the divisor is 10, 100, 1000, 10000, &c., point off as many figures from the right of the dividend, as there are ciphers in the divisor; the figures on the left of the point will be the quotient, and those on the rigid the remainder. Ex.... | |
 | James Bates Thomson - Arithmetic - 1846 - 362 pages
...many dollars ? Ans. $25. Note. — To divide by 10, 100, &c., is simply cutting off as many figures from the right of the dividend as there are ciphers in the divisor. (Art. 80.) Hence, 2O9. To reduce cents to dollars, cut off two figures on the right. To reduce mills... | |
 | James Bates Thomson - Arithmetic - 1846 - 402 pages
...many dollars ? Ans. $25. Note. — To divide by 10, 100, &c., is simply cutting off as many figures from the right of the dividend as there are ciphers in the divisor. (Art. 80.) Hence, 3OO> To reduce cents to dollars, cut off two figures on the right. To reduce mills... | |
 | James Bates Thomson - Arithmetic - 1846 - 354 pages
...many dollars ? Ans. $25. Note. — To divide by 10, 100, &c., is simply cutting off as many figures from the right of the dividend as there are ciphers in the divisor. (Art. 80.) Hence, 209. To reduce cents to dollars, cut off two figures on the right. To reduce mills... | |
 | James Bates Thomson - Arithmetic - 1848 - 432 pages
...how many cents ? Ans. 26 cents. Note.—To divide by 10,100, &c., we simply cut off as many figures from the right of the dividend as there are ciphers in the divisor. (Art. 131.) Hence, 372. To reduce cents to dollars, cut off two figures on the right. To reduce mills... | |
| |
To divide by 10, 100, &c., is simply cutting off as many figures from the right of the dividend as there are ciphers in the divisor. 
