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Divide the first term of the remainder by the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product from the first remainder, and so on : IV.
University Algebra: Embracing a Logical Development of the Science, with ... - Page 36
by Charles Davies - 1870

## An Introduction to Algebra: Being the First Part of a Course of Mathematics ...

Jeremiah Day - Algebra - 1814 - 304 pages
...first term, for the first term of the required root: Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferiour power, and multiplied by the index of the given power ,-f the quotient...

## An Introduction to Algebra: Being the First Part of a Course of Mathematics ...

Jeremiah Day - Algebra - 1827 - 352 pages
...first term, for the first term of the required root : Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferior power, and multiplied by the index of the given power ;t the quotient...

## Elements of Algebra

William Smyth - Algebra - 1830 - 278 pages
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient ; 4°. multiply the whole divisor by the second...

## A Practical System of Algebra: Designed for the Use of Schools and Private ...

Peter Nicholson - Algebra - 1831 - 326 pages
...term of the root. W Raise this quotient to the given power, and subtract it from the dividend ; then divide the first term of the remainder by the first term of the divisor, and it will give the next term of the quotient, proceed in a similar manner till the whole is finished....

## Elements of Algebra: Tr. from the French of M. Bourdon, for the ..., Volume 1

Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...of the quotient; multiply the divisor by this term, and subtract the product from the dividend. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by this second term, and subtract...

## Elements of Algebra

Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second...

## Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ...

Charles Davies - Algebra - 1835 - 378 pages
...division polynomials we have the following RULE. on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the fast term of the divisor, which gives...

## First Lessons in Algebra: Being an Easy Introduction to that Science ...

Ebenezer Bailey - Algebra - 1835 - 258 pages
...term, and subtract the product from the dividend. Divide the first term of the remainder by the Jirst term of the divisor, for the second term of the quotient. Multiply the whole divisor by this second term, and subtract the product from the remainder. Continue this series...