| Jeremiah Day - Algebra - 1814 - 304 pages
...first term, for the first term of the required root: Subtract the power from the given quantity, and **divide the first term of the remainder, by the first term of the** root involved to the next inferiour power, and multiplied by the index of the given power ,-f the quotient... | |
| Jeremiah Day - Algebra - 1827 - 352 pages
...first term, for the first term of the required root : Subtract the power from the given quantity, and **divide the first term of the remainder, by the first term of the** root involved to the next inferior power, and multiplied by the index of the given power ;t the quotient... | |
| William Smyth - Algebra - 1830 - 278 pages
...whole divisor by the term of the quotient just found, and subtract the result from the dividend ; 3°. **divide the first term of the remainder by the first term of the divisor,** the result will be the second term of the quotient ; 4°. multiply the whole divisor by the second... | |
| Peter Nicholson - Algebra - 1831 - 326 pages
...term of the root. W Raise this quotient to the given power, and subtract it from the dividend ; then **divide the first term of the remainder by the first term of the divisor,** and it will give the next term of the quotient, proceed in a similar manner till the whole is finished.... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...of the quotient; multiply the divisor by this term, and subtract the product from the dividend. Then **divide the first term of the remainder by the first term of the divisor,** which gives the second term of the quotient ; multiply the divisor by this second term, and subtract... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; **multiply the divisor by this term, and subtract the product from the** dividend. Divide the first term of this remainder by the first term of the divisor, and the second... | |
| Charles Davies - Algebra - 1835 - 378 pages
...division polynomials we have the following RULE. on the left of the divisor, the result is the first **term of the quotient ; multiply the divisor by this term, and subtract the product from the** dividend. II. Then divide the first term of the remainder by the fast term of the divisor, which gives... | |
| Ebenezer Bailey - Algebra - 1835 - 258 pages
...term, and subtract the product from the dividend. Divide the first term of the remainder by the Jirst **term of the divisor, for the second term of the quotient. Multiply the** whole divisor by this second term, and subtract the product from the remainder. Continue this series... | |
| Mathematics - 1836 - 530 pages
...divide the first term in the dividend by the first in the divisor, and write the result as the first in **the quotient ; multiply the divisor by this term, and subtract the product from the** di6 a 6s + б Ь3 vidend ; proceed to deal with the remainder, if any, in the same way. 43. By applying... | |
| Mathematics - 1836 - 488 pages
...first term, for the first term of the required root. Subtract the power from the given quantity, and **divide the first term of the remainder by the first term of the** root, involved to the next inferior power, and multiplied by the index of the given power ; the quotient... | |
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