A Textbook on Surveying and Mapping ...: Geometrical drawing, tables and formulasInternational Textbook Company, 1898 - Surveying |
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ACBG allel altitude angle of 45 arcs cutting axis base Bearing bisect blades Cast Iron center line mn chord circumference compasses cone CONSTRUCTION.-In Fig convenient radius Cosine Sine Cosine Cotang Tang Cotang cylinder cylindrical surface describe an arc describe arcs Diff DIFFERENCES OF ELEVATION dimensions Dist DISTANCES AND DIFFERENCES dotted lines draw the center draw the lines Draw the plan DRAWING PLATE edge ELEVATION FOR STADIA ellipse figure front elevation frustum given point guide lines helix hole HORIZONTAL DISTANCES horizontal line irregular curve letters line drawn lines A B needle point number of equal paper parallel sides pencil perpendicular points of intersection prism PROBLEM Project the points protractor radii radius equal right angles shown in Fig side elevation Sine Cosine Sine slant slant height square STADIA MEASUREMENTS student Tang Cotang Tang tangent tion triangle wwww wwww ΙΟ
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Page 64 - The curve formed by the intersection of a cone by a plane parallel to one of its elements is called a parabola. The plan and front elevations of the cone and curve of intersection are found in a manner similar to the method used in the last problem. To find the side elevation, proceed as follows : Draw the side elevation O" A" B" of the cone with the center line tv as its axis.
Page 54 - O of the two center lines as a center, and with a radius equal to the radius of the hole, describe a circle. Through the points A, B, E, and F, draw indefinite straight lines parallel to m n. On both sides of the center line/ q, lay off on these lines DS and SA, equal to £ DA, and HR and RE, equal to £ HE, both DA and HE being measured on the frustum. Through the points...
Page 29 - Ex. 3. — To draw a perpendicular to a straight line, from a given point in that line, Fig.
Page 41 - AC should be, for this plate, 1^" long. Produce AC to B. From C as center, with a radius equal to CA, describe the semicircle A 128456 7 B, and divide it into as many equal parts as there are sides in the required polygon (in this case eight). From the point C, and through the second division from B, as 6, draw the straight line C6.
Page 45 - COB. 1. — The area of a sector is equal to one-half the product of the radius into the arc of the sector.
Page 45 - Given the area of a circle, to find its diameter: Rule. — Divide the area by .7854, and extract the square root of the quotient.
Page 45 - To find the area of a segment of a circle: Rule. — Draw radii from the center of the circle to the extremities of the arc of the segment ; find the area of the sector thus formed, subtract from this the area of the triangle formed by the radii and the chord of the arc of the segment, and the result is the area of the segment.
Page 57 - GH indicates that only a part of the rivet is shown. This is done so as not to take up too much space on the drawing. Fig. 9 shows an ordinary square-headed bolt ^" in diameter, having a head If...
Page 38 - O is equally distant from A, B and C, since it lies in the perpendiculars to the middle points of AB and A C. Hence the circumference will pass through A, B and C. PROBLEM 14. To inscribe a Circle in a given Triangle. Draw the triangle LMN of any convenient size. MN may be made 3^ inches, LM, 2| inches, and LN, 3* inches.