 | Mathematics - 1801 - 446 pages
...product 36 ? Ans. 2 and 18. 2. To divide the number 60 into two such parts, that their product may be to the sum of their squares in the ratio of 2 to 5. Ans. 20 and 40. 3. The differe.nce of two numbers is 3, and the difference of their cubes is 117; what are those numbers... | |
 | John Bonnycastle - Algebra - 1811 - 230 pages
...theix product 36? Ans. 2 and 18. 2. To divide the number 60 into two such parts, that their product may be to the sum of their squares in. the ratio of 2 to 5. Ans. 20 and 40. 3. The difference of two numbers is 3, and the difference of theix cubes 13 H7; what are those numbers?... | |
 | John Bonnycastle - Algebra - 1813 - 456 pages
...and one of the parts shall be equal to the square of the other. Ans. 10/5 — 10 5. It is required to divide the number 60 into two such parts, that their...their squares in the ratio of 2 to 5. Ans. 20 and 40 6. It is required to divide 146 into two such parts, that the difference of their square roots may... | |
 | John Bonnycastle - Algebra - 1818 - 326 pages
...and one of the parts shall be equal to the square of the other. Ans. lOv/6-10 5. It is required to divide the number 60 into two such parts, that their...their squares in the ratio of 2 to 5. Ans. 20 and 40 6. It is required to divide the number 146 into such two parts, that the difference of their square... | |
 | John Bonnycastle - Algebra - 1818 - 284 pages
...given, Therefore ,T=16 — 4=12, the less number, And x+8= 12+8=50, the greater. 2. It is required to divide the number 60 into two such parts, that their product shall be 864. Let ,T=tbe greater part, Then will 60—z=the less, And.T(60-z)=60x -.T3=864, by the question,... | |
 | Jeremiah Day - Algebra - 1820 - 352 pages
...and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their. product shall be to the sum of their squares, as 3 to 1 0. Ans. 1 8 and 6. 13. In a mixture of rum and brandy, the difference between the quantities... | |
 | Bewick Bridge - Algebra - 1821 - 284 pages
...j/)'=72, Again, x*—2xу+у'=4, and 4xy =96. or ж+^=ю,| but x— y=2 ; Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. : ANSWER, 18 and 6. Ex. 7. There are two numbers which are to each other as 3 : 2. If 6... | |
 | Francis Tillett - Algebra - 1824 - 94 pages
...6=16=3/, and the two required numbers are 4 and 16. 16+4=20, and 16X4=64. }. Proof. 6. It is required to divide the number 60 into two such parts that their product shall be=756. ч First 60-=-2 orѕ4-»=30=w; then 30— dx 30+d=756, fey the question; and 30— dx30+d=900—... | |
 | Peter Nicholson - Mathematics - 1825 - 1046 pages
...but x* + 2.n/+y= lOO, }ia . . , = = 2 -*, — 8 — У 2 6. It is required to divide the number 24 into two such parts, that their product shall be to the sum of their squares :: 3 : 1O. Ans. 18 and 6. 7. There are two numbers which are to each other as 3 : 2. If б le added... | |
 | John Bonnycastle - Algebra - 1825 - 336 pages
...given, Therefore ar=16 — 4=12, the less number, and x+6 =12+8=20, the greater. 2. It is required to divide the number 60 into two such parts, that their product shall be 864. , Let x= th,e greater part, Then will 60— x = the less, And ar(60— z)-= 60x— z3= 864, by... | |
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Divide the number 24 into two such parts, that their product shall be to the sum of their squares, as 3 to 10. 
