 | Euclid, John Keill - Geometry - 1733 - 444 pages
...= Cot. B. Wherefore R x Cof. BC=Cot. Cx Cot. B ; that is, Radius drawn into the Sine of the. middle Part, is equal to the Product of the Tangents of the adjacent extreme Parts. : X And And BA, AC, are the oppofite Extremes to the faid middle Part, viz. the Complement... | |
 | William Chauvenet - 1852 - 268 pages
...considered, the two sides including it are regarded as adjacent. The rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness... | |
 | Elias Loomis - Trigonometry - 1855 - 192 pages
...found by the following RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner in remembering this... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...when either of the five parts is chosen as the middle part. NAPIER'S RULES, I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now... | |
 | Elias Loomis - Logarithms - 1859 - 372 pages
...found by the following RULE OF NAPIER. (211.) The product of the radius and the sine of the middle part, is equal to the product of the tangents of the adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner in remembering this... | |
 | Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...one of the following invariable and comprehensive rules : 1. The radius into the sine of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal to the product of the cosines of the opposite parts.... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...the five parts is chosen as the middle part. 90°-B 90° -T NAPIER'S RULES. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now... | |
 | 1860 - 462 pages
...middle pari equals the product of the cosines of the opposite parts. RULE II. The sine of the middle part is equal to the product of the tangents of the adjacent parts. That the second of these rules may be deduced from the first has been shown by Mr. SAFFORD, in No.... | |
 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...parts. Then, whatever be the middle part, we have as THE RULES OF NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of tJie cosines of the opposite parts. 168.... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...parts. Then, whatever be the middle part, we have as THE EULES OF NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168.... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. 
