 | Joseph Ray - Algebra - 1848 - 250 pages
...ONE POSITIVE MONOMIAL BY ANOTHER. Multiply the coefficients of the two terms together, and to their product annex all the letters in both quantities,...the sum of its exponents in the two factors. NOTE. — It is customary to write the letters in the order of the alphabet. Thus, aiXc is generally written... | |
 | Joseph Ray - Algebra - 1848 - 252 pages
...POSITIVE MONOMIAL BY ANOTHER. Wultiply the coefficients of the two terms together, and to their proditct annex all the letters in both quantities, giving to...the sum of its exponents in the two factors. NOTE. — It is customary to write the letters in the order of the alphabet. Thus, 06 Xc is generally written... | |
 | William Smyth - Algebra - 1851 - 272 pages
...in arithmetic. 2°. To this product annex all the letters in each of the factors, observing to give to each letter an exponent equal to the sum of its exponents in the factorS. XXVIII. In the preceding examples the quantities to be multiplied are each positive. 1. Let... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...the sum of its exponents in the two factors. This is termed the rule of the exponents. E XAM PLE 8. ART. 57. From the two preceding articles we derive...alphabetically. EXAMPLES. 1. Multiply be by z. Ans. Icz. 2. Multiply Sax by by. Ans. Salxy. 3. Multiply 4am by Sbn. Ans. IZabmn. 4. Multiply 5a2a; by 7ax3y.... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...ONE POSITIVE MONOMIAL BY ANOTHER. Multiply the coefficients of the two terms together, and to their product annex all the letters in both quantities,...the sum of its exponents in the two factors. NOTE. — It is customary to write the letters in the order of the alphabet. Thus, aiXc is generally written... | |
 | Thomas Sherwin - Algebra - 1855 - 262 pages
...Multiply the coefficients together, and write after their product all the different letters of the several quantities, giving to each letter an exponent equal to the sum of its exponents in all the quantities. 1. Multiply 3а2 m by 4 а3 m5. In this question, the product of the coefficients... | |
 | Charles Davies - Algebra - 1859 - 324 pages
...together for a new coefficient : П. Write after this coefficient all the letters in both mono miaLt, giving to each letter an exponent equal to the sum of its tsrpanenU in the too factors. К X » il PLES. 8. 21a3oW x Sabe3 = 168a4oVcí. S 4abc X Vf// = IBab/xif.... | |
 | Charles Davies - Algebra - 1860 - 330 pages
...all the letters in both mono42. What is the rale for multiplying one monomial by another ? 3* mials, giving to each letter an exponent equal to the sum of its exponents in the two factors. EXAMPLES. 1. 8rt25c2 X labcP = 2. IlaWcd x 8a5c3 = 168a453c4c?. 3 4a5c X 1df — ZBabcdf. (4.) * (5.)... | |
 | Thomas Sherwin - 1862 - 252 pages
...Multiply the coefficients together, and write after their product all the different letters of the several quantities, giving to each letter an exponent equal to the sum of its exponents in all the quantities. 1. Multiply 3a 2 m by 4a 3 m 5 . In this question, the product of the coefficients... | |
 | Benjamin Greenleaf - 1863 - 338 pages
...Multiply the numerical coefficients of the two factors together, and annex to the result the letters of both quantities, giving to each letter an exponent...equal to the sum of its exponents in the two factors. Make the product positive, when the factors have like signs, and negative when they have different... | |
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Multiply the coefficients of the two terms together, and to their product annex all the letters in both quantities, giving to each letter an exponent equal to the sum of its exponents in the two factors. 
