 | William Taylor (teacher of the mathematics.) - Arithmetic - 1800 - 556 pages
...the perpendicular height, the produel will be the area ; or multiply the bafe by the perpendicular, and half the product will be the area. EXAMPLE i. What is the area of a triangle, whofe bafe B is 36 feet, and perpendicular height H 16 feet ? i 63 Or thus : 16 36 _ Anf. 288 Anf.... | |
 | Thomas Hodson - Education - 1806 - 576 pages
...RULE. Multiply the fum of the two parallel fides by half the perpendicular diftance between then), and the product will be the area. EXAMPLE i. What is the area of a trapcfoid, whofe two parallel fides are 8 feet and i» feet, and perpendicular diftaace 10 feet ? 8... | |
 | Thomas Hodson - Arithmetic - 1806 - 502 pages
...FIG. g. The area of all triangles is found by- the following rules : — RULE i. Multiply the bafe by the perpendicular height, and half the product will be the area. But when only the three fides of the triangle are given, the area is found by the following rule: —... | |
 | Isaac Dalby - Mathematics - 1807 - 968 pages
...remaining shall be equal to 5 square 1ч i ? Ans. lOj'r inches. To find the urea of a Trianglt, 257. MULTIPLY the base by the perpendicular height, and half the product will be the area. Or multiply the base by half the height, or the height by halt the base. • For a triangle U equal... | |
 | Isaac Dalby - Mathematics - 1807 - 476 pages
...shall be equal to 5 square feet? Ans. 10TV inches. To find the urea of a Triangle. 257. MuLTiPLYthe base by the perpendicular height, and half the product will be the area. Or multiply the base by half the height, or the height by half the base. For a triangle is equal to... | |
 | James Thompson - Arithmetic - 1808 - 176 pages
...and its height 9 feet 3 inches ! Ata. 115/f. 7 in. 6". II. To ßnd the area of a triangle. RULE — Multiply the base by the perpendicular height, and half the product will be theurea. EXAMPLES. 9. Required the area of the triangle whose base is 10 feet 9 inches, and height... | |
 | Peter Nicholson - 1809 - 426 pages
...the' area of a rhomboides ABCD, whose length AB is l6f. 3i. and the height DE 5f. 6i. ? PROBLEM II. To find the area of a triangle. Multiply the base...height, and half the product will be the area. EXAMPLE 1. I What is the area of a triatgk ABC, the base AB being 12f. 3i. and the height BC 8f. 6i.? By duodecimals.... | |
 | John Gummere - Surveying - 1814 - 398 pages
...PROBLEM II. To find the area of a triangle when the base and per pendicular height are given. RULE. Multiply the base by. the perpendicular height, and half the product will be the area.* • DEMONSTRATION. A triangle is half a parallelogram of the same base and altitude (41.1.), and therefore... | |
 | Thomas Keith - 1817 - 306 pages
...cxc D x natural sine of the angle c — the area. PROBLEM IV. Tofind the Area of a Triangle. RULE. Multiply the base by the perpendicular height, and half the product will be the area *. Example 1. If the base of a triangle be 15'4 inches, and the perpendicular 7'8 inches, what is the area ? Am.... | |
 | John Nicholson (civil engineer.) - Great Britain - 1825 - 1008 pages
...the area of a rhombus, whose length is 6 chains, and perpendicular height 5. - 5 5 Ansr. 30 Proli. 2. To find the Area of a Triangle. /.'•'/..• ]. Multiply...perpendicular height, and half the product will be the area. Rule 2. When the three sides only are given : Add the three sides together, and take half the sum ;... | |
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To find the Area of a Triangle. /.'•'/..• ]. Multiply the base by the perpendicular height, and half the product will be the area. 
