## Euclidian Geometry |

### From inside the book

Results 1-5 of 14

Page 72

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**twice the squares**on half the line and on the line between the points of section . = Let AH be divided into two ... the square on AC . ( I. 35 ) Join FH ; draw DK || to CF ; KG || to AH ; join AK . Then it may be easily shewn that FCH ... Page 73

... squares on half the base and on the line joining the vertex and the middle point of the base . K C H From the vertex K of △ AKH draw KD 1 to AH . Bisect AH in C , and join CK . Then shall the squares on AK , KH =

... squares on half the base and on the line joining the vertex and the middle point of the base . K C H From the vertex K of △ AKH draw KD 1 to AH . Bisect AH in C , and join CK . Then shall the squares on AK , KH =

**twice**... the square on DK ... Page 84

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**the square**on S is > the**squares**on A and B by**twice**the rect- angle A , B. Also , if A and B be unequal and D be their difference , the rectangle S , D is = the difference between the**squares**on A , B ; and**the square**on D is < the ... Page 85

... square on D + twice rectangle A , B = squares on A , B. COR . It follows from the proposition that squares on S , D + twice rectangle A , B =

... square on D + twice rectangle A , B = squares on A , B. COR . It follows from the proposition that squares on S , D + twice rectangle A , B =

**twice squares**on A , B + twice rectangle A , B ; .. squares on S , D =**twice squares**on A , B. Page 86

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**the square**on the side opposite the obtuse angle is greater than the**squares**on the sides contain- ing it by**twice**...**squares**on AC , CB by**twice**the rectangle AC , CK . For AK is the sum of AC and CK ; = ..**square**on AK is =**squares**on AC ...### Other editions - View all

### Common terms and phrases

Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex