## Euclidian Geometry |

### From inside the book

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Page vii

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**perimeters**of regular polygons inscribed in and circumscribed about a circle have been discussed , and the groundwork laid for a comparison not only of the areas but also of the circumferences of circles . It has been deemed essential ... Page 154

... one another , as are also AHB , BIC , & c . Hence the difference between the polygons ABC ... , and HIJ ... is equal to polygon XYZ .... I. COR . 1. If the polygons are formed by AREAS AND

... one another , as are also AHB , BIC , & c . Hence the difference between the polygons ABC ... , and HIJ ... is equal to polygon XYZ .... I. COR . 1. If the polygons are formed by AREAS AND

**PERIMETERS**OF INSCRIBED AND H ... Page 155

... a circle whose area shall differ from that of the circle by less than any assignable area : so also can one be circumscribed about it , & c . PROBLEM 15 . To find the difference between the

... a circle whose area shall differ from that of the circle by less than any assignable area : so also can one be circumscribed about it , & c . PROBLEM 15 . To find the difference between the

**perimeters**AREAS AND**PERIMETERS**. 155. Page 156

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**perimeter**of this polygon is equal to the difference between the**perimeters**of the polygons ABC , HIJ . COR . I. If the polygons are formed by continual 156 AREAS AND**PERIMeters**. Page 157

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**perimeter**of the square on a side of the inscribed polygon . ( III . c ) COR . 2 . Hence a polygon can be inscribed in a circle whose**perimeter**shall differ from that of the circumference of the circle by less than any assignable ...### Other editions - View all

### Common terms and phrases

Algebra base Cambridge centre chord circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle Latin Let ABC line bisecting locus Mathematical meet opposite angles Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively revised rhombus right angles Schools Second Edition segment similar Similarly squares on AC straight line drawn straight line joining tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex