Euclidian Geometry |
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Page 114
... be situated in one of the arms AP of the LAPB . Then ... CP = CB ; . : . LCPB = LCBP ; ( Ι . 2 ) but ACB = ∠s CPB , CBP ; ( Ι . 24 ) ... LACB is double of 2 CPB ; i . e . LAPB . 2ndly . Let Clie within the LAPB . P C ANGLES IN CIRCLES .
... be situated in one of the arms AP of the LAPB . Then ... CP = CB ; . : . LCPB = LCBP ; ( Ι . 2 ) but ACB = ∠s CPB , CBP ; ( Ι . 24 ) ... LACB is double of 2 CPB ; i . e . LAPB . 2ndly . Let Clie within the LAPB . P C ANGLES IN CIRCLES .
Page 115
... it to meet the Oce in V. Then BCY is double of 2 BPY , and ACV is double of LAPY ; remaining ACB is double of APB . DEFINITION . An angle in a segment is the angle 8-2 ANGLES IN CIRCLES . 115 2ndly. Let Clie within the LAPB. ...
... it to meet the Oce in V. Then BCY is double of 2 BPY , and ACV is double of LAPY ; remaining ACB is double of APB . DEFINITION . An angle in a segment is the angle 8-2 ANGLES IN CIRCLES . 115 2ndly. Let Clie within the LAPB. ...
Page 118
... LAPB in the semicircle is a right 2 . Again , ... the 2 SAPB , ABP are together < two rt . 2 s , ( 1.13 ) APB is a right ∠ ; segment ABP greater than a semi- and ... LABP in the circle is < a right 4 . Also , . ABPQ is a quadrilateral ...
... LAPB in the semicircle is a right 2 . Again , ... the 2 SAPB , ABP are together < two rt . 2 s , ( 1.13 ) APB is a right ∠ ; segment ABP greater than a semi- and ... LABP in the circle is < a right 4 . Also , . ABPQ is a quadrilateral ...
Page 187
... LAPB = L ZQY , ( III . 14 ) also LPBA = L QYZ ; ... APB is equiangular to AZQY ; .. AP : ZQ as AB : ZY ; ... square on AP : square on ZQ as ( III . 16 ) ( Ι . 25 ) ( VI . 4 ) square on AB : square on ZY . ( VI . 9 ) And since polygon ...
... LAPB = L ZQY , ( III . 14 ) also LPBA = L QYZ ; ... APB is equiangular to AZQY ; .. AP : ZQ as AB : ZY ; ... square on AP : square on ZQ as ( III . 16 ) ( Ι . 25 ) ( VI . 4 ) square on AB : square on ZY . ( VI . 9 ) And since polygon ...
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Common terms and phrases
Algebra ATHENĈUM base Cambridge centre chord Christ's College circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided draw a straight ELEMENTARY TREATISE English equiangular equilateral Euclid Extra fcap fcap GEOMETRY given angle given circle given point given straight line Grammar greater Hence inscribed intersecting isosceles triangle LAPB Latin Let ABC line bisecting locus Mathematical meet Owens College parallel parallelogram perimeter perpendicular plane polygon PROBLEM produced Professor proportional PROPOSITION ratio rect rectangle rectangle contained rectilineal figure regular polygon respectively rhombus right angles Schools Second Edition segment Similarly squares on AC straight line drawn straight line joining student tangent THEOREM TRIGONOMETRY twice rectangle twice the squares vertex