| Mathematics - 1801 - 446 pages
...what had he at first ? Ans. 2os. 21. To divide the number 90 into 4 such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2t" the sum, difference, product, and quotient, shall be all equal to each other. Ans. The parts are... | |
| John Bonnycastle - Algebra - 1806 - 234 pages
...divide the number 90 into four fuch parts, that if the firft be increafed by 2, the fecond diminifhed by 2, the third multiplied by 2, and the fourth divided by 2; the A1m, difference, product, and quotient fhall be all equal to each other. Ans. The parts are 1 8,... | |
| Samuel Webber - Mathematics - 1808 - 466 pages
...what had he at first ? Ans. 2Os. 21. To divide the number 90 into 4 such parts, that, if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient, shall be all equal to each other. Ans. The parts are. 18,... | |
| John Bonnycastle - Algebra - 1811 - 230 pages
...had he at first ? Ans. 20s. 21. To divide the number 9ft into four such parts, that if the first be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2; the sum, difference, product, and quotient shall be all equal to each other. Ans. The parts are 18,... | |
| John Bonnycastle - Algebra - 1813 - 456 pages
...Ans. 300 36. It is required to divide the number 90 into four soch parts, that if the first part be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient shall be all equal ? Ans. The parts are 18, 22, 1O, and... | |
| Bewick Bridge - Algebra - 1818 - 254 pages
...the digits will be inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second...by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18, 22, 10, 40. Qu. 34. A merchant has two kinds often, one worth 95. 6uf.... | |
| John Bonnycastle - Algebra - 1818 - 326 pages
...Ans. 300 32. It is required to divide the number 90 into four such parts, that if the first part be increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference, product, and quotient, shall be all equal ? Ans. The parts are 18, 22, 10, and... | |
| Adrien Marie Legendre - Geometry - 1819 - 574 pages
...the other 402. 64. To divide the number 90 into four such parts that if the first be increased by Z, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, the sum, difference} product, and quotient shall each equal the same quantity. Ans. The parts are 18,... | |
| Jeremiah Day - Algebra - 1820 - 352 pages
...the first horse by 13 guineas. What' is the value of each horse ? Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first...increased by 2, the second diminished by 2, the third multipled by 2, and the fourth dividedny 2, shall all be equal. If oc, y, and z, be three of the parts,... | |
| Bewick Bridge - Algebra - 1821 - 648 pages
...the digits will be inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second...by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18,22,10,40. Qu. 34. A merchant has two kinds of tea, one worth Qs.&d.... | |
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