 | Euclid, John Bascombe Lock - Euclid's Elements - 1892 - 188 pages
...indefinitely ; prove that the sum of the areas PAB, PAD is equal to the area PAC. Proposition 47. 145. In a right-angled triangle the area of the square described...hypotenuse is equal to the sum of the areas of the squares described upon the other two sides of the triangle. Let ABC represent a triangle in which the angle... | |
 | 1902 - 482 pages
...a right-angled triangle, and show that the area of the square on the side opposite the right angle is equal to the sum of the areas of the squares on the other two sides. 9. Find area of the curved surface of a cylinder by wrapping paper round it. 10. Find... | |
 | W. T. Clough - Chemistry - 1907 - 204 pages
...and between the same parallels are equal. Expt. 89 In a right.angled triangle the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the other two sides. Test this statement by drawing the figures on squared paper, and then counting the... | |
 | Elmer Adelbert Lyman - Geometry - 1908 - 364 pages
...described on the other two sides. Given : A right.angled A ABC. To Prove: That the area of the square on AB is equal to the sum of the areas of the squares on AC and CB. Proof: Construct the squares ABED, BCGF, and ACHI on AB, CB, and AC respectively. Draw CJ... | |
 | Trinity College (Dublin, Ireland) - 1911 - 614 pages
...triangles are described on the sides of a right-angled triangle, prove that the area of the triangle described on the hypotenuse is equal to the sum of the areas of the two others. 10. Show how to construct a rectilinear figure of given area similar to a given... | |
 | Frank Eugene Austin - Electric currents, Alternating - 1916 - 270 pages
...of the large square ACHG. FIG. 2. FIG. 3. It is therefore evident that the area of the square ACHG on the .hypotenuse is equal to the sum of the areas of the squares on the other two sides. Another graphical proof for a particular condition, would be to draw the hypotenuse... | |
 | Frank Eugene Austin - Electric currents, Alternating - 1916 - 260 pages
...square ACHG. FIG. 2. FIG. 3. It is therefore evident that the area of the square ACHG on the^hypotenuse is equal to the sum of the areas of the squares on the other two sides. Another graphical proof for a particular condition, would be to draw the hypotenuse... | |
 | William Ledley Vosburgh, William Frederick Gentleman - Mathematics - 1918 - 232 pages
...each of the sides of the right triangle ABC. Show that the area of -nM -in j\ 7i FIG. 48. the square on the hypotenuse is equal to the sum of the areas of the squares on the two legs. SOLUTION. The area of the square on AC = 12 X 12 = 144 The area of the square on EC = 16... | |
 | Eugene Herz, Mary G. Brants - Arithmetic - 1920 - 344 pages
...the fact that when squares are drawn on all three sides of a right triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the two other sides. This rule is known as the Pythagorean theorem. To prove that this is so, we need only... | |
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Put another way, if you construct squares on the edges of a right-angled triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the other two sides. 
